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3 years ago

HELP!!!!!!!!!!! Please like fast please and thank you

Mathematics

2 answers:

Andrej [43]3 years ago

7 0

C is the concrete one that has

Maslowich3 years ago

3 0

Answer:

Step-by-step explanation:

39-7=32

40-7=33

41-7=34

42-7=35

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What is 8 Divided by 231 to the nearest thousandth

Mkey [24]

Answer:

0.346

Step-by-step explanation:

brainiest pls ty

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1 year ago

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Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y

sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is $z = 7 \sin (v)$ and the interval for u is $0\le u\le 1$ .

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder $y^2+z^2 = 49$ , that lies between the places x = 0 and x = 1.

$x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?$

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

$0\le u\le 1$

Equation for z.

Replacing the given equation for the parameterization $y = 7 \cos(v)$ on the given equation for the cylinder give us

$(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49$

Solving for z, by moving $49 \cos^2 (v)$ to the other side

$z^2 = 49-49 \cos^2 (v)$

Factoring

$z^2 = 49(1- \cos^2 (v))$

So then we can apply Pythagorean Theorem:

$\sin^2(v)+\cos^2(v) =1$

And solving for sine from the theorem.

$\sin^2(v) = 1-\cos^2(v)$

Thus replacing on the exercise we get

$z^2 = 49\sin^2 (v)$

So we can take the square root of both sides and we get

$z = 7 \sin (v)$

4 0

3 years ago

What are the domain and range of the logarithmic function f(x) = log7x? Use the inverse function to justify your answers.

S_A_V [24]

Answer:

Step-by-step explanation:

Since log is defined by all positive real numbers

therefore domain is all positive real number that is ( 0,∞)

Range is given by real numbers

inverse of the given function is (10^x)/7

Whose domain is all real numbers and range is all positive real number

And since we know that domain of function and range of its inverse

& range of a function and domain of its inverse is same

which we are getting in the problem

so answer is justified

6 0

3 years ago

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Given: m

Nutka1998 [239]

Answer:

$m\angle MEJ=25^{\circ}.$

Step-by-step explanation:

The arcs LY, KM, KL and MJ together form the full revolution angle, thus

$4x+50^{\circ}+6x+x+10^{\circ}+4x=360^{\circ},\\ \\15x=300^{\circ},\\ \\x=20^{\circ}.$

Note that

$m\angle MOJ=4x=80^{\circ},$

then

$m\angle MLJ=\dfrac{1}{2}\cdot 80^{\circ}=40^{\circ}.$

So,

$m\angle ELM=180^{\circ}-40^{\circ}=140^{\circ}.$

Also

$m\angle LOK=30^{\circ},$

$m\angle KML=\dfrac{1}{2}\cdot 30^{\circ}=15^{\circ}.$

In triangle EML,

$m\angle MEL+m\angle EML+m\angle ELM=180^{\circ},\\ \\m\angle MEL=180^{\circ}-15^{\circ}-140^{\circ}=25^{\circ}.$

Thus, $m\angle MEJ=25^{\circ}.$

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3 years ago

The sixth graders have a fundraising goal of $480. They have reached 3/4 of their goal so far. How much money have they raised?

melisa1 [442]

Answer:

$360

Step-by-step explanation:

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2 years ago

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