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Goryan [66]
3 years ago
15

HELP!!!!!!!!!!! Please like fast please and thank you

Mathematics
2 answers:
Andrej [43]3 years ago
7 0
C is the concrete one that has
Maslowich3 years ago
3 0

Answer:

C

Step-by-step explanation:

39-7=32

40-7=33

41-7=34

42-7=35

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-14+7-9r+13r someone please helpp !
JulsSmile [24]

Answer:

4r-7

Step-by-step explanation:

-14+7-9r+13r

combine like terms

4r-14+7

combine like terms

4r-7

hope this helped :)

4 0
3 years ago
Read 2 more answers
Can someone help please​
Jlenok [28]

Answer:

11/8 or, 1 and 3/8

Step-by-step explanation:

First, we have to make both the denominators the same. In this case, we can multiply 3/4 by 2, to make 4, the denominator, into 8. What we do to the denominator, we must do to the numerator! So, we multiply 3 by 2, and get 6!

Now we have, 5/8 + 6/8, which equals 11/8! Which can also be simplified to 1 and 3/8 (because the numerator is larger than the denominator)

Hope this helps! :)

5 0
3 years ago
The Wall Street Journal reports that 33% of taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deduction
Len [333]

Answer:

(a) <em>                             </em><em>n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b) The correct option is (b).

Step-by-step explanation:

Let the random variable <em>X</em> represent the amount of deductions for taxpayers with adjusted gross incomes between $30,000 and $60,000 itemized deductions on their federal income tax return.

The mean amount of deductions is, <em>μ</em> = $16,642 and standard deviation is, <em>σ</em> = $2,400.

Assuming that the random variable <em>X </em>follows a normal distribution.

(a)

Compute the probability that a sample of taxpayers from this income group who have itemized deductions will show a sample mean within $200 of the population mean as follows:

  • For a sample size of <em>n</em> = 20

P(\mu-200

                                           =P(-0.37

  • For a sample size of <em>n</em> = 50

P(\mu-200

                                           =P(-0.59

  • For a sample size of <em>n</em> = 100

P(\mu-200

                                           =P(-0.83

  • For a sample size of <em>n</em> = 500

P(\mu-200

                                           =P(-1.86

<em>                                  n</em> :      20           50          100         500

P (-200 < <em>X</em> - <em>μ </em>< 200) : 0.2886    0.4444    0.5954    0.9376

(b)

The law of large numbers, in probability concept, states that as we increase the sample size, the mean of the sample (\bar x) approaches the whole population mean (\mu_{x}).

Consider the probabilities computed in part (a).

As the sample size increases from 20 to 500 the probability that the sample mean is within $200 of the population mean gets closer to 1.

So, a larger sample increases the probability that the sample mean will be within a specified distance of the population mean.

Thus, the correct option is (b).

8 0
3 years ago
he following data represent the times in minutes required for 18 co-workers to commute to work. 48 42 31 29 41 22 38 38 21 39 22
labwork [276]

Answer:

1, 2, 2, 2, 3, 8, 9

Step-by-step explanation:

The following data represent the times in minutes required for 18 co-workers to commute to work

48 42 31 29 41 22 38 38 21 39 22 48 22 12 34 32 23 28

Rewrite this data in ascending order

12 21 22 22 22 23 28 29 31 32 34 38 38 39 41 42 48 48    

Now, the stem-and-leaf plot is

\begin{array}{cc}\text{Stem}&\text{Leaf}\\ \\1&2\\2&1,2,2,2,3,8,9\\3&1,2,4,8,8,9\\4&1,2,8,8\end{array}

The second row represents the leaves for the given data points in the range 20 to 29 for this stem-and-leaf plot, so the answer is

1, 2, 2, 2, 3, 8, 9

3 0
3 years ago
The Ortiz family will travel round-trip from Indianapolis to Denver this summer. The driving distance between the two cities is
MatroZZZ [7]
The gas will cost $1,528.82.
7 0
3 years ago
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