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Ivanshal [37]
3 years ago
6

If light intensity obeyed an inverse square law you would expect to find the intensity of light to decrease as the square of the

distance increases?
True or false
Physics
2 answers:
mezya [45]3 years ago
8 0

this is a true statement

Reptile [31]3 years ago
4 0
Inverse square law: \frac{I_{2} }{I_{1}}= (\frac{d{2} }{d_{1}})^2
where 
I_{1} is the intensity at distance 1
I_{2} is the intensity at distance 2
d_{1} is distance 1
d_{2} is distance 2

The inverse squared law state that intensity decreases in inverse proportion to the distance squared. So if light obeyed that rule, it will decreases its intensity as the square of the distance increases.

We can conclude that the correct answer is: true.
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As per the given Figure attached here we know that both charges q1 and q2 will apply same force on charge q3 and hence the resultant force due to both charges will be along Y axis vertically upwards

So here we know that

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now from the above equation

F = \frac{(9\times 10^9)(2\times 10^{-6})(4 \times 10^{-6})}{0.5^2}

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now we have

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