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3 years ago

12

Transformers will not work on ______ electrical systems.

2 answers:

Andru [333]3 years ago

5 0

Transformers only work with AC.

If you put DC into a transformer, all that comes out is smoke.

(a)

Sphinxa [80]3 years ago

3 0

Transformers will not work on direct current in electrical systems.

Answer: Option A

<u>Explanation: </u>

Transformers work only on the alternate current of electrical system. And they are not suitable to work upon with the direct current. As the direct current has the property to transfer high voltage directly and is unable to direct the current with high and low voltages, causes the transformer to burn out the coil leading to burning of the transformer circuit and causing smoked transformers.

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How many electrons must be removed from each of two 4.85-kg copper spheres to make the electric force of repulsion between them

VladimirAG [237]

Answer:

$n=2.611*10^{9}electrons$

Explanation:

Given data

mass of copper m=4.85 kg

charge of electron qe= -1.6×10⁻¹⁹C

To find

Number of electron n must be removed

Solution

Equate the magnitude of electric force Fe of repulsion between two two spheres to the magnitude of gravitational force of attraction between them

So

$F_{e}=F_{g}\\ k\frac{q_{e}q_{e}}{r^{2} }=G\frac{m^{2} }{r^{2} }\\ k(q_{e})^{2}=Gm^{2}\\$

where q is charge of each sphere which is equal to number n of removed electrons multiplied by each charge qe

So

$k(nq_{e})^{2}=Gm^{2}\\n=\sqrt{\frac{Gm^{2}}{k(q_{e})^{2}} }\\ n=\sqrt{\frac{(6.67*10^{-11}N.m^{2}/kg^{2})(4.85kg)^{2}}{(8.99*10^{9}N.m^{2}/C^{2} )(1.6*10^{-16}C)^{2}} }\\n=2.611*10^{9}electrons$

3 0

3 years ago

according to Newton's __ law, an object with no net force acting on it remains at rest or in motion with a constant veloctiy

Pani-rosa [81]

Answer:

i think its his law of inertia

Explanation:

this law is about motion

5 0

2 years ago

The change in state of a liquid to a gas

ioda

evaporation (if that's to fill in the blanks question)

6 0

3 years ago

Read 2 more answers

A wave has a frequency of 15,500 Hz and a wavelength of 0.20 m. What is the

Hoochie [10]

Answer:

3100 m/s

Explanation:

The relationship between frequency and wavelength of a wave is given by the wave equation:

$v=f\lambda$

where

v is the speed of the wave

f is its frequency

$\lambda$ is the wavelength

For the wave in this problem,

f = 15,500 Hz

$\lambda=0.20 m$

Therefore, the wave speed is

$v=(15500)(0.20)=3100 m/s$

4 0

3 years ago

A tree loses water to the air by the process of transpiration at the rate of 110 g/h. This water is replaced by the upward flow

Ksivusya [100]

Answer:

The answer is 1.87nm/s.

Explanation:

The $110g/hr$ water loss must be replaced by $110g/hr$ of sap. 110g of sap corresponds to a volume of

$110g \div \dfrac{1040*10^3g}{1*10^6cm^3} = 106cm^3$

thus rate of sap replacement is

$106cm^3/hr = 106*10^{-6}m^3/3600s = 2.94*10^{-8}m^3/s$

The volume of sap in the vessel of length $x$ is

$V = Ax$ ,

where $A$ is the cross sectional area of the vessel.

For 2000 such vessels, the volume is

$V = 2000Ax$

taking the derivative of both sides we get:

$\dfrac{dV}{dt} = 2000A \dfrac{dx}{dt}$

on the left-hand-side $\dfrac{dx}{dt}$ is the velocity $v$ of the sap, and on right-hand-side $\dfrac{dV}{dt} = 2.94*10^{-8}m^3/s$ ; therefore,

$2.94*10^{-8}m^3/s=2000Av$

and since the cross-sectional area is

$A = \pi (\dfrac{100*10^{-3}m}{2} )^2 = 7.85*10^{-3}m^2$ ;

therefore,

$2.94*10^{-8}m^3/s =2000(7.85*10^{-3}m^2)v$

solving for $v$ we get:

$v = \dfrac{2.94*10^{-8}m^3/s}{2000(7.85*10^{-3}m^2)}$

$\boxed{v =1.875*10^{-9}m/s = 1.875nm/s}$

which is the upward speed of the sap in each vessel.

8 0

3 years ago