Answer:
Average angular velocity ≈ 4.59 rad/s
Explanation:
Using the equation of motion,
H = ut + (1/2)t² ............................ equation 1.
Where H= height, u = initial velocity(m/s), g = acceleration due to gravity(m/s²), t = time(s) u= 0 ∴ ut =0
H =(1/2)gt².................................... equation 2.
making t² the subject of the relation in equation 2,
∴ t² = 2H/g
Where H = 9.2 m, g= 9.8 m/s
∴ t² = ( 2×9.2)/9.8
t = √(2 × 9.2/9.8) = √(18.4/9.8)
t = 1.37 s.
The average angular velocity = θ/t
Where θ = is the number of revolution that the diver makes, t = time
θ = 1 rev.
Since 1 rev = 2π (rad)
t = 1.37 s
Average angular velocity = 2π/t
π = 3.143
Average angular velocity = (2×3.143)/1.37 = 6.286/1.37
Average angular velocity ≈ 4.59 rad/s
