Consider a box weight 2700 newtons resting on the ground. If the area of the box touching the ground is 1.5 square meters, what
1 answer:
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Answer:
x=31.09m
Explanation:
p1=p2
The momentum of flatcar and the momentum of the worker so
The velocity of the worker is:
The total motion has a total velocity and is
The time the worker take walking is
Now the total time and the total velocity determinate the motion of tha flatcar how far has moved
Answer:
(C) Decreases by factor of 3
Explanation:
Centripetal acceleration is given by
where <em>v</em> is the linear velocity and <em>r</em> is the radius of the curve.
Let the centripetal acceleration on the curve of radius <em>R</em> be .
Then
Let the centripetal acceleration on the curve of radius 3<em>R</em> be .
Then
Here, we see that the acceleration decreases by a factor of 3.
75.17 mg of the radioactive substance will remain after 24 hours.
Answer:
Explanation:
Any radioactive substance will obey the exponential decay behavior. So according to this behavior, any radioactive substance will be decaying in terms of exponential form of disintegration constant and Time.
Disintegration constant is the rate of decay of radioactive elements. It can be measured using the half life time of the radioactive element .While half life time is the time taken by any radioactive element to decay half of its concentration. Like in this case, at first the scientist took 200 mg then after 17 hours, it got reduced to 100 g. So the half life time of this element is 17 hours.
Then Disintegration constant = 0.6932/Half Life time
Disintegration constant = 0.6932/17=0.041
Then as per the law of disintegration constant:
Here N is the amount of radioactive element remaining at time t and is the initial amount of sample, x is the disintegration constant.
So here, = 200 mg, x = 0.041 and t = 24 hrs.
N = 200 × =75.17 mg.
So 75.17 mg of the radioactive substance will remain after 24 hours.