Will two sounds of 50 db constitute a sound of 100 db . Explain
1 answer:
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Answer:
The work done on the object by the force in the 5.60 s interval is 40.93 J.
Explanation:
Given that,
Force
Mass of object = 2.00 kg
Initial position
Final position
Time = 4.00 sec
We need to calculate the work done on the object by the force in the 5.60 s interval.
Using formula of work done
Put the value into the formula
Hence, The work done on the object by the force in the 5.60 s interval is 40.93 J.
The velocity of the brick is 39.2 m/s downward
Explanation:
The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of .
So, we can find its velocity using the suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the brick in this problem (taking downward as positive direction)
u = 0 (it is dropped from rest)
Therefore, its velocity after t = 4.0 s is:
Downward, because the sign is positive.
Learn more about free fall motion:
#LearnwithBrainly
Answer:
_s = 37.77 m / s
Explanation:
This is an exercise of the Doppler effect that the change in the frequency of the sound due to the relative speed of the source and the observer, in this case the observer is still and the source is the one that moves closer to the observer, for which relation that describes the process is
f ’= f₀
where d ’= 530 Make
when the ambulance passes away from the observer the relationship is
f ’’ = f₀
where d ’’ = 424 beam
let's write the two expressions
f ’ (v-v_s) = fo v
f ’’ (v + v_s) = fo v
let's solve the system, subtract the two equations
v (f ’- f’ ’) - v_s (f’ + f ’’) = 0
v_s = v
the speed of sound is v = 340 m / s
let's calculate
v_s = 340
v_s = 340 )
v_s = 37.77 m / s