Answer:
α = 3×10^-5 K^-1
Explanation:
let ΔL be the change in length of the bar of metal, ΔT be the change in temperature, L be the original length of the metal bar and let α be the coefficient of linear expansion.
then, the coefficient of linear expansion is given by:
α = ΔL/(ΔT×L)
= (0.3×10^-3)/(100)(100×10^-3)
= 3×10^-5 K^-1
Therefore, the coefficient of linear expansion is 3×10^-5 K^-1
Answer:
A. 148.23 m
B. 2.75 m/s
Explanation:
The following data were obtained from the question:
Time of flight (T) = 11 s
Maximum height (h) =?
Initial velocity (u) =?
Next, we shall determine the time taken for the ball to get to the maximum height. This can be obtained as follow:
Time of flight (T) = 11 s
Time (t) to reach the maximum height =.?
T = 2t
11 = 2t
Divide both side by 2
t = 11/2
t = 5.5 s
NOTE: Time to reach the maximum height is the same as the time taken for the ball to fall back to the plane of projection.
A. Determination of the maximum height to which the ball was thrown.
Time (t) to reach maximum height = 5.5 s
Acceleration due to gravity (g) = 9.8 m/s²
Maximum height (h) =?
h = ½gt²
h = ½ × 9.8 × 5.5²
h = 4.9 × 30.25
h = 148.23 m
B. Determination of the initial velocity.
Maximum height (h) reached = 148.23 m
Acceleration due to gravity (g) = 9.8 m/s²
Initial velocity (u) =?
u² = h/2g
u² = 148.23 / (2 × 9.8)
u² = 148.23 / 19.6
Take the square root of both side
u = √(148.23 / 19.6)
u = 2.75 m/s
Answer:
A) t = 0.55 s
B) x = 24.8 m
Explanation:
A) We can find the time at which the ball will be in the air using the following equation:
Where:
is the final height= 0
is the initial height= 1.5 m
is the component of the initial speed in the vertical direction = 0 m/s
t: is the time =?
g: is the gravity = 9.81 m/s²
By solving the above equation for t we have:
Hence, the ball will stay 0.55 seconds in the air.
B) We can find the distance traveled by the ball as follows:
Where:
a: is the acceleration in the horizontal direction = 0
is the final position =?
is the initial position = 0
is the component of the initial speed in the horizontal direction = 45 m/s
Therefore, the ball will travel 24.8 meters.
I hope it helps you!
Answer:
(A) Force on the object will be 58.85 N
(B) Apparent weight will be equal to 57.21 N
Explanation:
We have given mass of Neptune m = 1026 kg
Radius R = 25000 Km
Time period = 16 hour
We know that 1 hour = 3600 sec
So 16 hour = 16×86400 = 57600 sec
Acceleration due to gravity at north pole of Neptune 
(A) Mass of the object m = 5.5 kg
So gravitational force on the object 
(B) Velocity will be equal to 
Apparent weight of the object will be equal to 
