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s344n2d4d5 [400]
3 years ago
10

What is the volume of 12.8 g of a liquid that has a density of 0.789 g/mL?

Chemistry
2 answers:
shusha [124]3 years ago
4 0
  <span> .789=12.8*x
.789/12.8=x
.0616=x
.0616ml </span>
Paha777 [63]3 years ago
4 0

<u>Answer:</u> The volume of liquid is 16.22 mL.

<u>Explanation:</u>

Density is defined as the ratio of mass of the object and volume of the object.

Mathematically,

\text{Density}=\frac{\text{Mass of the object}}{\text{Volume of the object}}

We are given:

Density of liquid = 0.789g/mL

Mass of liquid = 12.8 g

Putting values in above equation, we get:

0.789g/mL=\frac{12.8g}{\text{Volume of liquid}}\\\\\text{Volume of liquid}=16.22mL

Hence, the volume of liquid is 16.22 mL.

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8 0
3 years ago
Based on the equation, how many grams of Br2 are required to react completely with 36.2 grams of AlCl3?
s2008m [1.1K]

Answer:

65.08 g.

Explanation:

  • For the reaction, the balanced equation is:

<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

<em>n = mass/molar mass</em> = (36.2 g)/(133.34 g/mol) = <em>0.2715 mol.</em>

<u><em>Using cross multiplication:</em></u>

2.0 mole of AlCl₃ reacts with → 3.0 mole of Br₂, from the stichiometry.

0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

∴ The no. of moles of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃  = (0.2715 mol)(3.0 mole)/(2.0 mole) = 0.4072 mol.

<em>∴ The mass of Br₂ reacts completely with 0.2715 mol (36.2 g) of AlCl₃ = no. of moles of Br₂ x molar mass</em> = (0.4072 mol)(159.808 g/mol ) = <em>65.08 g.</em>

4 0
3 years ago
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