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4 years ago

Plz.. help me this out I am from nepal actually it is math

Physics

1 answer:

Ierofanga [76]4 years ago

4 0

Answer:

tan (x eˣ) + C

Explanation:

∫ (eˣ + x eˣ) / (cos² (x eˣ)) dx

First, use u-substitution.

u = x eˣ

du = (eˣ + x eˣ) dx

∫ 1 / (cos² u) du

∫ sec² u du

tan u + C

Substitute back:

tan (x eˣ) + C

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Answer:

The deceleration is $a = - 76.27 m/s^2$

Explanation:

From the question we are told that

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The length by which the net is stretched is $s = 1.8 \ m$

From the law of energy conservation

$KE_T + PE_T = KE_B + PE_B$

Where $KE_T$ is the kinetic energy of the person before jumping which equal to zero(because to kinetic energy at maximum height )

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and $KE_B$ is the kinetic energy of the person just before landing on the safety net which is mathematically represented at

$KE_B = \frac{1}{2} m v^2$

and $PE_B$ is the potential energy of the person as he lands on the safety net which has a value of zero (because it is converted to kinetic energy )

So the above equation becomes

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=> $v = \sqrt{2 gH }$

substituting values

$v = 16.57 m/s$

Applying the equation o motion

$v_f = v + 2 a s$

Now the final velocity is zero because the person comes to rest

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$a = - \frac{16.57^2 }{2 * 1.8}$

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3 years ago

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