To solve this problem with the given elements we will apply the linear motion kinematic equations. We will start by calculating the time taken, with the vertical displacement data. Subsequently, with the components of the acceleration, we will obtain the magnitude of the total acceleration, to finally obtain the horizontal displacement with the data already found.
PART A) From vertical movement we know that the acceleration is equivalent to gravity and the displacement is 8m so the time taken to carry out the route would be
Here,
Replacing,
PART B) Now, Magnitude of acceleration
Thus, magnitude of net acceleration
PART C) Finally the displacement along horizontal direction is:
Therefore the distance traveled along the horizontal direction before it hits the ground is 3.098m
Answer: the work done by the force is 0
Explanation:
F (x², xy)
121 = 11²
so R = x² + y² = 11²
p = x². Q = xy
Δp/Δy = 0, ΔQ/Δx
using Green's theorem
woek = c_∫F.Δr = R_∫∫ ΔQ/Δx - Δp/Δy) ΔA
= (x² + y² = 121)_∫∫ yΔA
now let x = rcosФ, y = rsinФ
ΔA = rΔrΔФ
so r from 0 to 11
and Ф from 0 to 2π
= 0_∫^2π 0_∫^11 rsinФ × rΔrΔФ
= 0_∫^2π SinФΔФ 0_∫^11 r²Δr
= [ -cosФ]^2π_0 [r³/3]₀¹¹ = ( -cos2π + cos0) (11³/3) = 0
therefore the work done by the force is 0
Answer:
Explanation:
The total fluid mass can be obtained by multiplying the mass flow rate by the time flow rate.
Mass flow rate is given as
m = ρAv
Where
m is mass flow rate
ρ is density
A is area and it is given as πr²
v is velocity
Then,
M = mt
Where M is mass and t is time
Them,
M = ρAv × t
M = ρ× πr² × v × t
Given that, .
Radius of pipe is
r = 0.089m
velocity of pipe is
v = 3.3m/s
Time taken is
t = 1 hour = 3600 seconds
Density of water is
ρ = 1000kg/m³
M = ρ× πr² × v × t
M = 1000 × π × 0.089² × 3.3 × 3600
M = 295,628.52 kg
M = 2.96 × 10^5 kg
Since both cars move together after the collision, then this is an example of an inelastic collision. The formula for an inelastic collision is as follows:
m1u1 + m2u2 = (m1 + m2)v
Where:
m1 = mass of the first object
m2 = mass of the second object
u1 = initial velocity of the first object
u2 = initial velocity of the second object
v = final velocity
Substituting the given values to solve for v:
900*22 + 900*15 = (900 + 900)v
v = 18.5 m/s
Answer: 20496N
Explanation:
The formula to calculate the net force will be given as:
Net force = Acceleration × Mass
Since 10248 kg car is pulled by a low tow truck that has an acceleration of 2.0m/s, the net force would be:
= 10248 × 2
= 20496N
