Question

The Electric Potential Difference Created by Point Charges 13. Two point charges, +3.40 pC and -6.10 uC, are separated by 1.20 m. What is the electric potential midway between them?

Answer 1

Answer:

- 91499.95 V

Explanation:

Let the mid point is P.

qA = 3.4 pC = 3.4 x 10^-12 C

qB = - 6.10 micro Coulomb = - 6.10 x 10^-6 C

AB = 1.20 m

AP = BP = 0.6 m

Let the potential at P due to the charge at A is VA and the potential at P due to the charge at B is VB.

The potential at P is V

V = VA + VB

$V = \frac{Kq_{A}}{AP}+\frac{Kq_{B}}{BP}$

$V = \frac{9\times 10^{9}\times 3.4\times 10^{-12}}{0.6}-\frac{9\times 10^{9}\times 6.10\times 10^{-6}}{0.6}$

V = 0.051 - 91500

V = - 91499.95 V