I’m pretty sure it’s an insulator
Answer:
a) Em= K +U, b) Em= K
Explanation:
The system in this case is formed by the mobilizes and the hill.
Let's write the expressions correctly and completely.
a) When the car moves in the path, the mechanical energy is the siua of the kinetic energy of the car and the potential energy of the car when going up the hill.
Em = K + U
be) when the car moves in the flat part all the mechanical energy is formed by its kinetic energy that is calculated with the mass and speed of the car
Em = K
c) When the car goes up the hill the energy the mechanical energy is conserved, but part of the kinetic energy is transformed into potential energy.
Answer:
<em>The non resonance frequency of the generator is = 1201.79 Hz</em>
Explanation:
At resonance,
f₀ = 1/2π√LC..................... Equation 1
Where f₀ = resonance frequency, L = inductance, C = capacitance
making LC the subject of the equation
LC = 1/4πf₀²..................... Equation 2
<em>Given: </em>f₀ = 225 Hz, and π = 3.143
<em>Substituting these values into equation 2,</em>
LC = 1/(4×3.143²×225²)
LC = 1/2000385.9
LC = 5×10⁻⁷
If the ratio of capacitive reactance to inductive reactance = 5.36
1/2πfC/2πfL = 5.36
1/4π²f²LC = 5.36
Where f = frequency of the non resonant
making f the subject of the equation
f = 5.36/2π√LC ............. Equation 3
Substituting the value of LC = 5×10⁻⁷ into equation 3
f = 5.36/2×3.143√(5×10⁻⁷)
f = 5.36/(6.286×0.00071)
f = 5.36/0.00446
<em>f = 1201.79 Hz</em>
<em>Thus the non resonant frequency of the generator is = 1201.79 Hz</em>
Angular speed must such a cylinder have so that the centripetal acceleration at its surface equals the free-fall acceleration on Earth is 0.0466 rad/s.
Length of the cylinder, L = 9 mi
= (14.5mi)(1609.344 m / 1 mi)
= 23,335.48 m
Diameter of the cylinder, D = 4.78 mi
= (4.78 mi)(1609.344 m / 1 mi)
= 7692.645 m
Radius of the cylinder, r = D / 2
= ( 7692.645 m) / 2
= 3846.32 m
Centripetal acceleration is given by, ac = v^2 / r
We have the relation between linear velocity (v) and the angular velocity(ω) as
v = r ω
Then, ac = v2 / r
= (rω)2 / r
ac = ω^2 r
If the centripetal acceleration is equals the free fall acceleration of earth, then
ω^2 r = g
ω=0.0466 rad/s
- Angular acceleration is the term used to describe the rate of change in angular velocity. If the angular velocity is constant, the angular acceleration is constant.
To know more about angular velocity visit : brainly.com/question/12446100
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