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Brrunno [24]
3 years ago
7

We do not get hurt while jumping of aeroplane with a parachute,Why?​

Physics
1 answer:
SashulF [63]3 years ago
8 0

Answer:

this is because of air resistance

Explanation:

air resistance is a type of friction in air. It acts on the parachute as an upward force and slows the person speed while falling.

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Label and describe what is happening in this picture
SOVA2 [1]
Something is reproducing.
7 0
3 years ago
Two blocks with masses M1 and M2 hang one under the other.
Anna35 [415]

Answer:

(a)T= M2 × g,    (b)T= (M1 + M2)g,   (c)T= M2 (a + g) and  (d)T=(M1 + M2) (a + g)

Explanation:

M1 is hanged upper and M2 is lower at Rest.

(a) For M2

T2 = Weight of the Body M2= M2 × g

(b) T1 = Weight of the Body M2 + Weight of the Body M2

T1 = M1 g + M2 g = (M1 + M2)g

M1 is hanged upper and M2 is lower at accelerated upwards ( F = T - W)

(c) For M2

⇒T = M2a + M2g = M2 (a + g)

(d) For M1

T = (M1 + M2) a + (M1 + M2) g

⇒ T = (M1 + M2) (a + g)

5 0
3 years ago
Read 2 more answers
What is the closed physical system?
Alexus [3.1K]
Answer:D
A system where matter and energy can not enter or leave the system
8 0
3 years ago
What can you conclude about the pendulum at the instant shown by the graph below (just past 2 s)?
Semenov [28]
Below are the chocies 
A. The pendulum is at its highest point. 
<span>B. The pendulum is 0.9 m above its lowest point. </span>
<span>C. The pendulum is between its highest and lowest points. </span>
<span>D. The pendulum is at its lowest point. 
</span>
I think the answer is C.. 

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
7 0
4 years ago
During a 400-m race, a runner crosses the 100 m mark with a velocity of 12 m/s. What would be her final position if she maintain
Cerrena [4.2K]

Answer:

Explanation:

Given that

Total race distance is 400m

Her initial velocity was 0m/s²

At the 100m mark, after she has travelled 100m, her final velocity was v=12m/s²

Using equation of motion

Let determine her constant acceleration

v²=u²+2as

12²=0²+2×a×100

144=0+200a

144=200a

a=144/200

a=0.72m/s²

Then we want to know her position after another 10second

So total time is 10+12=22seconds

Then, using equation of motion

Let determine his postion

S=ut+½at²

S=0•t+½×0.72×22²

S=0+174.24

S=174.24 m

Her position will be 174.24m

7 0
4 years ago
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