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3 years ago

PLz help! Help me with number 6!

Mathematics

2 answers:

sammy [17]3 years ago

7 0

4 cm squared because you count the whole shaded squares and add up the halves.

Nataly [62]3 years ago

5 0

4 because 1 triangle = 1/2. And there are 4 triangles in it, so it will be 2, then there are 2 squares that equal 2, so 2 + 2 = 4.

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Solve the triangle for x.

nalin [4]

Answer:

90.4°

Step-by-step explanation:

Use Law of Cosines to solve:

12² = 9² + 8² - 2(9)(8)Cos X

144 = 81 + 64 - 144Cos X

-1 = -144Cos X

-1/144 = Cos X

Cos^-1 (-1/144) = X

X = 90.39789056°

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2 years ago

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Answer:

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3 years ago

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Answer:

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3 years ago

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7 is one tenth of what number

Sloan [31]

Answer:

Explanation:

Assume that the number we are looking for is x

one tenth is interpreted into $\frac{1}{10}$

Now, we know that one tenth of the number is 7, this means that:

$\frac{1}{10}$ * x = 7

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$\frac{1}{10}$ * x * 10 = 7 * 10

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Hope this helps :)

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3 years ago

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In a parallelogram ABCD point K belongs to diagonal BD so that BK:DK=1:4. If the extension of AK meets BC at point E, what is th

olya-2409 [2.1K]

Answer:

$\frac{BE}{EC} =\frac{1}{3}$

Step-by-step explanation:

In the diagram below we have

ABCD is a parallelogram. K is the point on diagonal BD, such that

$\frac{BK}{CK} =\frac{1}{4}$

And AK meets BC at E

now in Δ AKD and Δ BKE

∠AKD =∠BKE ( vertically opposite angles are equal)

since BC ║ AD and BD is transversal

∠ADK = ∠KBE ( alternate interior angles are equal )

By angle angle (AA) similarity theorem

Δ ADK and Δ EBK are similar

so we have

$\frac{AD}{BE} =\frac{DK}{BK}$

$\frac{AD}{BE} =\frac{4}{1}$

$\frac{BC}{BE}=\frac{4}{1}$ ( ABCD is parallelogram so AD=BC)

$\frac{BE+EC}{BE}=\frac{4}{1}$ ( BC= BE+EC)

$\frac{BE}{BE} +\frac{EC}{BE}=\frac{4}{1}$

$1+\frac{EC}{BE}=4$

$\frac{EC}{BE}=3$ ( subtracting 1 from both side )

$\frac{EC}{BE}=\frac{3}{1}$

taking reciprocal both side

$\frac{BE}{EC} =\frac{1}{3}$

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3 years ago