Answer:
Explanation:
A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1
Answer:
3.33 L
Explanation:
We can solve this problem by using the equation:
Where the subscript 1 refers to one solution and subscript 2 to the another solution, meaning that in this case:
We input the data:
- 0.25 M * 100 L = 7.5 M * V₂
Thus the answer is 3.33 liters.
Answer: C
Explanation: Took the test
There are spaces between particles of matter. The average amount of empty space between molecules gets progressively larger as a sample of matter moves from the solid to the liquid and gas phases. There are attractive forces between atoms/molecules, and these become stronger as the particles move closer together.