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postnew [5]
2 years ago
13

What keeps some of the radiation from the Sun in the atmosphere?

Chemistry
2 answers:
Yanka [14]2 years ago
5 0
The appropriate answer is b. greenhouse gases. Greenhouse gases such as carbon dioxide and methane have the ability to trap infrared radiation or heat in the atmosphere. Without these gases the Earth would be thirty degrees cooler than it is today. Pollution today has caused more of these gases to enter the atmosphere and this is the main cause of contemporary global warming.
Ozone in the stratosphere actually blocks another form of radiation called ultraviolet radiation. Geothermal energy is derived from hot rocks inside the earth.
nalin [4]2 years ago
3 0
The O-Zone protects earth from the sun's harmful rays and keeps the air we breath within our planets boundaries.
You might be interested in
12.
Veronika [31]

Answer:

Nonbonding pairs of electrons.

Explanation:

Both oxygen atoms in the diatomic molecule have two nonbonding pairs. This results in the oxygen molecule having a planar geometric shape. This is because nonbonding pairs repel each other are significant in determining the shape of a molecule.

3 0
3 years ago
Read 2 more answers
A sample of gas has a volume of 4.4 liters when the pressure is 3.3atm. What is the volume when the pressure is reduced to 2.2at
oee [108]
You'll remain with 2.9 liter
4 0
3 years ago
Whats two answers I know B is wrong
JulijaS [17]

Answer:A and D

Explanation:

6 0
2 years ago
Read 2 more answers
What would happen if a cell membrane let too much water into a cell?
Sloan [31]

Answer:

<u>Animal Cell</u>

  • When water moves into an animal cell (e.g. a red blood cell), the cell membrane stretches and the cell gets bigger. If this continues, the cell membrane will burst – this is called lysis.

<u>Plant Cell</u>

  • When too much water moves out of a plant cell the cell contents shrink. This pulls the cell membrane away from the cell wall. A plasmolyzed cell is unlikely to survive.

8 0
2 years ago
Read 2 more answers
At equilibrium, the concentrations of the products and reactants for the reaction, H2 (g) + I2 (g)  2 HI (g), are [H2] = 0.106
lana [24]

Answer:

The new equilibrium concentration of HI: <u>[HI] = 3.589 M</u>          

Explanation:

Given: Initial concentrations at original equilibrium- [H₂] = 0.106 M; [I₂] = 0.022 M; [HI] = 1.29 M        

Final concentrations at new equilibrium- [H₂] = 0.95 M; [I₂] = 0.019 M; [HI] = ? M

<em>Given chemical reaction:</em> H₂(g) + I₂(g) → 2 HI(g)

The equilibrium constant (K_{c}) for the given chemical reaction, is given by the equation:

K_{c} = \frac {[HI]^{2}}{[H_{2}]\: [I_{2}]}

<u><em>At the original equilibrium state:</em></u>

K_{c} = \frac {(1.29\: M)^{2}}{(0.106\: M) \times (0.022\: M)}

K_{c} = \frac {1.6641}{0.002332} = 713.59

<u><em>Therefore, at the new equilibrium state:</em></u>

K_{c} = \frac {[HI]^{2}}{(0.95\: M) \times (0.019\: M)}

\Rightarrow K_{c} = 713.59 = \frac {[HI]^{2}}{0.01805}

\Rightarrow [HI]^{2} = 713.59 \times 0.01805 = 12.88

\Rightarrow [HI] = \sqrt {12.88} = 3.589 M

<u>Therefore, the new equilibrium concentration of HI: [HI] = 3.589 M</u>

6 0
2 years ago
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