How many moles of carbon are in 7.87*10^7 carbon atoms
2 answers:
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Answer:
Percent yield of SiC is 77.0%.
Explanation:
Balanced reaction:
Molar mass of SiC = 40.11 g/mol
Molar mass of = 60.08 g/mol
So, 100.0 kg of =
moles of
= 1664 moles of
According to balanced equation, 1 mol of produces 1 mol of SiC
Therefore, 1664 moles of produce 1664 moles of SiC
Mass of 1664 moles of SiC = = 66743g = 66.74 kg (4 sig. fig.)
Percent yield of SiC = [(actual yield of SiC)/(theoretical yield of SiC)]%
= %
= 77.0%
Answer:
7.7439×10⁻³¹ m
Explanation:
The expression for Heisenberg uncertainty principle is:
Where m is the mass of the microscopic particle
h is the Planks constant
Δx is the uncertainty in the position
Δv is the uncertainty in the velocity
Given:
mass = 0.68 g = 0.68×10⁻³ kg
Δv = 0.1 m/s
Δx= ?
Applying the above formula as:
<u>Δx = 7.7439×10⁻³¹ m</u>