Answer: B) 2 (as indicated by electron distribution shown), but taking into account the real properties of this element, 4,7,8 also occur (see below).
Explanation:
This is the electron complement/atomic number of ruthenium, which actually has the structure [Kr] 5s1 4d7
Nevertheless, Ru does not form Ru(I) compounds and few Ru(II) compounds (RuCl2, RuBr2, RuI2). It also forms Ru(III)Cl3 and a larger number of Ru(IV) compounds, e.g. RuO2, RuS2. It also forms RuO4
Answer:
Number of boxes = 4
Explanation:
Given:
Mass of one box of jello = 250 grams
Total quantity want to purchase = 1 kg = 1 × 1,000 gram = 1,000 grams
Find:
Number of boxes in 1,000 grams = ?
Computation:
Number of boxes = Total quantity want to purchase / Mass of one box of jello
Number of boxes = 1,000 / 250
Number of boxes = 4
Therefore, 4 boxes of jello must be purchase to get 1 kg of Jello.
<span>If I done the math correctly it is 3729J because you multiply 16.5 g by the 2260 J/g and get 3729 J</span>