Question

8x+4y=16 ; 7y=15-x solve the system of equations given below

Answer 1

The answer is x=1 and y=2 hope it helps you dear

Answer 2

Answer:  (1,2)

Step-by-step explanation:

The given system of linear equations :-

$8x+4y=16 \\7y=15-x$ which can be written as ,

$2x+y=4..........(1) \text{[Divide both sides by 2]}\\7y+x=15................(2)\text{[Add x on both sides]}$

Now, Multiply 2 on both sides of equation (2), we get

$14y+2x=30.........(3)$

Subtract equation (1) from equation (3) , we get

$13y=26\\\\\Rightarrow\ y=2$

Put y= 2 in (1), we get

$2x+2=4\\\\\Rightarrow\ 2x=2\\\\\Rightarrow\ x=1$

Hence, the solution to the given system is (1,2).