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grandymaker [24]
3 years ago
5

A classroom contains 33 students. In the classroom, 6 students wear red shirts, 11 wear white shirts, 8 wear black shirts, and t

he remaining 8 students wear blue shirts. Mrs. Kulkarni randomly chooses a student to clean the whiteboard. Determine the probability that Mrs. Kulkarni selects a student wearing a red shirt. Enter your answer in the box.
Mathematics
2 answers:
-Dominant- [34]3 years ago
8 0

Answer:

She picked white because the board is white

inna [77]3 years ago
3 0

Answer:

24.24... percent chance

Step-by-step explanation:

Because 6/33 is 24 percent and 6 is the amount of red shirts

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katrin [286]

C' ( 0, 3)

A' ( 2 , 1)

C'A' = CA

C'A' = √(2^2 + 2^2) = √8 = 2√2

C'A' = CA = 2√2

3 0
3 years ago
A new sample of 225 employed adults is chosen. Find the probability that less than 7.1% of the individuals in this sample hold m
arsen [322]

Answer:

The probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

Step-by-step explanation:

Let <em>X</em> = number of individuals in the United States who held multiple jobs.

The probability that an individual holds multiple jobs is, <em>p</em> = 0.13.

The sample of employed individuals selected is of size, <em>n</em> = 225.

An individual holding multiple jobs is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 225 and <em>p</em> = 0.13.

But since the sample size is too large Normal approximation to Binomial can be used to define the distribution of proportion <em>p</em>.

Conditions of Normal approximation to Binomial are:

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  • n (1 - p) ≥ 10

Check the conditions as follows:

np=225\times 0.13=29.25>10\\n(1-p)=225\times (1-0.13)=195.75>10

The distribution of the proportion of individuals who hold multiple jobs is,

p\sim N(p, \frac{p(1-p)}{n})

Compute the probability that less than 7.1% of the individuals in this sample hold multiple jobs as follows:

P(p

*Use a <em>z</em>-table.

Thus, the probability that less than 7.1% of the individuals in this sample hold multiple jobs is 0.0043.

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Answer:

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Step-by-step explanation:

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Answer: 27.5

Step-by-step explanation:

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