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expeople1 [14]
3 years ago
6

Wyle

Physics
1 answer:
faust18 [17]3 years ago
3 0

Distance of a fall from rest  =  (1/2) (gravity) (time)²

                                         = (4.9 m/s²) (12.5 sec)²

                                         =  (4.9 · 12.5²)  m-sec² / sec²

                                         =    766 meters  (rounded)

Quite a high cliff !
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An 870 N firefighter, F_ff, stands on a ladder that is 8.00 m long and has a weight of 355 N, F_ladder. The weight of the ladder
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Explanation:

Weight of the ladder is 355N

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The weight of the ladder acts at center of the ladder I.e at 4m from the bottom

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Wf = 870N

The fire fighter is at 6.3m from the bottom of the ladder.

N1 is the normal force exerted  by the wall

N2 is the normal force exerted  by the ground

Using Newton law

Check attachment

ΣFy = 0, since body is in equilibrium

N₂ - WL - Wf = 0

N₂ = WL + Wf

N₂ = 870 + 355

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This the normal force exerted by the ground on the wall.

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ΣMa = 0

Clockwise moment is equal to anti-clockwise moment

Moment Is the produce of force and perpendicular distance.

M = F×r

So,

WL•Cos50 × 4 + Wf•Cos50 × 6.3 —N₁•Sin50 × 8 = 0

355•Cos50 × 4 + 870•Cos50 × 6.3 =

N₁•Sin50 × 8

1825.52 + 3523.12 = 6.13N₁

6.13N₁ = 5348.64

N₁ = 5348.64/6.13

N₁ = 872.54 N.

The normal force exerted by the wall is 872.54N

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3 years ago
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