3 years ago

Consider the rocket in the image. Which unbalanced force accounts for the direction of the net force of the rocket ?

Physics

2 answers:

olya-2409 [2.1K]3 years ago

6 0

Answer:

Gravity

Explanation:

Gravity is bringing down the rocket and is not air resistance

Wittaler [7]3 years ago

3 0

Answer:

unbalenced force

Explanation:

make Brainliest plz

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A 100-kg astronaut is floating in outer space. If the astronaut throws a 2-kilogram wrench at a speed of 10 meters per second, w

sergey [27]

Since Astronaut and wrench system is isolated in the space and there is no external force on it

So here momentum of the system will remain conserved

so here we can say

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}$

initially both are at rest

so here plug in all values

$0 = 100 v_{1f} + 2\times 10$

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3 years ago

To identify whether the forces are balanced or not, you need to whet

jok3333 [9.3K]

Answer:

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Explanation:

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3 years ago

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Annette [7]

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3 years ago

A refrigerator had a mass of 73 kg. What is the weight of the refrigerator in newtons

Sophie [7]

Answer:

715.4 N

Explanation:

W = mg

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3 0

2 years ago

Read 2 more answers

Hunter aims directly at a target (on the same level) 75.0 m away. (a) If the bullet leaves the gun at a speed of 180 m/sby how m

tankabanditka [31]

Answer:

Part a)

$\delta y = 0.85 m$

Part b)

$\theta = 0.65 degree$

Explanation:

Part a)

As we know that the target is at distance 75 m from the hunter position

so here we will have

$x = v_x t$

here we know that

$v_x = 180 m/s$

so we have

$75.0 = 180 (t)$

$t = 0.42 s$

now in the same time bullet will go vertically downwards by distance

$\delta y = \frac{1}{2}gt^2$

$\delta y = \frac{1}{2}(9.81)(0.42^2)$

$\delta y = 0.85 m$

Part b)

In order to hit the target at same level we need to shot at such angle that the range will be 75 m

so here we have

$R = \frac{v^2 sin(2\theta)}{g}$

$75 = \frac{180^2 sin(2\theta)}{9.81}$

$\theta = 0.65 degree$

4 0

4 years ago