How long tg does it take for the balls to reach the ground? use 10 m/s2 for the magnitude of the acceleration due to gravity.

Why do students and scientists construct scale models of natural phenomena? (1 point) Oto define new units of measurement O to c

KATRIN_1 [288]

Students and scientists construct scale models of natural phenomena to better observe patterns and relationships.

What is natural phenomena?

Things that happen naturally—phenomena—occur or show up without human intervention. Gravity, tides, moons, planets, volcanic lightning, starling swarms, ant armies, sandstorms, biological processes and oscillation, among countless more events, are examples of natural phenomena.

Scientists and students use models to help them visualize their current understanding of a system in the condition that it is in right now.

To learn more about natural phenomena click on the link below:

brainly.com/question/28585198

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6 0

2 years ago

Learning Goal: To practice Problem-Solving Strategy 7.1 Rotational dynamics problems. Suppose that you are holding a pencil bala

aliya0001 [1]

Answer:

when the pencil is balanced on a point it is motionless due to net force only acting trough the center, but when we release the position we are changing the location of a pencil hence due to turning affect it will expericence torque and the angular acceleration produced.

for the complete answer the length and mass of pencil should be known i am giving the general expression for the calculation of angular acceleration

Explanation:

<h3>τ=Iα</h3><h3>τ= torque</h3><h3>I = inertia</h3><h3>α= angular acceleration</h3>

where

I= mL^2/3 (by geometry of pencil)

when the pencil is released it will experience force due to weight

F=mgsinθ

so τ=Fxd

τ=mgsin(10°)x(L/2)

then.

α=τ/I

α=mgsin(10°)xL/2÷(mL^2)/3

6 0

3 years ago

Assume that Young’s modulus for a new material is known to be 2.25 × 1011 /2

Lady bird [3.3K]

Answer:

Maximum force, $F_{max} = 42 kN$

Explanation:

Maximum Stress, $\sigma_{max} = 2.1 * 10^{7} N/m^{2}$

The diameter of the material, d = 50.5 mm = 0.0505 m

The area of the material, $A = (\pi d^{2} )/4$

$A = \frac{\pi * 0.0505^{2} }{4} \\A = 0.002 m^{2}$

The formula for the maximum stress that the material can take is given by:

$\sigma_{max} = \frac{F_{max} }{A} \\2.1 * 10^7 = \frac{F_{max} }{0.002}\\F_{max} = 2.1 * 10^7 * 0.002\\F_{max} = 4.2 * 10^4 N\\F_{max} = 42 kN$

4 0

3 years ago

A 15 kg bucket of water is suspended by a very light ropewrapped around a solid uniform cylinder 0.300 m in diamter withmass 12.

matrenka [14]

Answer:

Part a)

$T = 42 N$

Part b)

$v_f = 11.8 m/s$

Part c)

$t = 1.7 s$

Part d)

$F = 159.7 N$

Explanation:

Part a)

While bucket is falling downwards we have force equation of the bucket given as

$mg - T = ma$

for uniform cylinder we will have

$TR = I\alpha$

so we have

$T = \frac{1}{2}MR^2(\frac{a}{R^2})$

$T = \frac{1}{2}Ma$

now we have

$mg = (\frac{M}{2} + m)a$

$a = \frac{mg}{(\frac{M}{2} + m)}$

$a = \frac{15 \times 9.81}{(6 + 15)}$

$a = 7 m/s^2$

now we have

$T = \frac{12 \times 7}{2}$

$T = 42 N$

Part b)

speed of the bucket can be found using kinematics

so we have

$v_f^2 - v_i^2 = 2 a d$

$v_f^2 - 0 = 2(7)(10)$

$v_f = 11.8 m/s$

Part c)

now in order to find the time of fall we can use another equation

$v_f - v_i = at$

$11.8 - 0 = 7 t$

$t = 1.7 s$

Part d)

as we know that cylinder is at rest and not moving downwards

so here we can use force balance

$F = T + Mg$

$F = 42 + (12 \times 9.81)$

$F = 159.7 N$

5 0

3 years ago

Do only number 5 and thank

Naddik [55]

Answer:

Quantity of charge = 1800 Coulombs

Explanation:

Given the following data;

Current = 1 A

Time = 0.5 hours

Conversion:

1 hour = 60 * 60 = 3600 seconds

0.5 hour = 0.5 * 3600 = 1800 seconds

To find the charge passing through the wire;

Mathematically, the quantity of charge passing through a conductor is given by the formula;

Quantity of charge = current * time

Substituting into the formula, we have;

Quantity of charge = 1 * 1800

Quantity of charge = 1800 Coulombs

8 0

3 years ago