How long tg does it take for the balls to reach the ground? use 10 m/s2 for the magnitude of the acceleration due to gravity.

Find the solution set of x + y = 5, 2 x - y = 7

STALIN [3.7K]

X + y = 5
x = 5 - y

2x - y = 7
2(5-y) - y = 7
10 - 2y - y = 7
10 - 3y = 7
10 - 7 = 3y
3 = 3y
y = 1

x + y = 5
x + 1 = 5
x = 5 - 1
x = 4

4 0

3 years ago

Galileo attempted to measure the speed of light by measuring the time elapsed between his opening a lantern and his seeing the l

Dafna11 [192]

Answer:

The distance is $2.58\times10^{7}\ m$ .

Explanation:

Given that,

Time $\Delta t = 0.2\ s$

The velocity is no more than a 14 % error in the speed of light.

So,

Velocity $v= c\times 86\%$

We need to calculate the distance

Using formula of speed

$v = \dfrac{d}{t}$

$d = v\times t$

Where, v = speed

d = distance

t = time

Put the value into the formula

$d = 3\times10^{8}\times\dfrac{86}{100}\times0.2$

$d=516\times10^{5}\ m$

We know that,

The one side distance d' is

$d'=\dfrac{d}{2}$

$d'=\dfrac{516\times10^{5}}{2}$

$d'=2.58\times10^{7}\ m$

Hence, The distance is $2.58\times10^{7}\ m$ .

5 0

3 years ago

Four velcro-lined air-hockey disks collide with each other in a perfectly

Reil [10]

Answer:

The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South

Explanation:

The given collision parameters are;

The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision

The mass of the first disk, m₁ = 50.0 g

The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i

The mass of the second disk, m₂ = 60.0 g

The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j

The mass of the third disk, m₃ = 100.0 g

The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i

The mass of the fourth disk, m₄ = 40.0 g

The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j

Therefore, the total initial momentum of the four velcro-lined air-hockey disk, $\Sigma P_{initial}$ is given as follows;

$\Sigma P_{initial}$ = m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)

∴ $\Sigma P_{initial}$ = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j

∴ $\Sigma P_{initial}$ = -20·i + 130·j

By the law of conservation of linear momentum, we have;

$\Sigma P_{initial} = \Sigma P _{final}$ = -20·i + 130·j

Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0

∴ m = 250.0 g

Let, "v" represent the final velocity of the four disks moving as one after the collision

We have;

$\Sigma P _{final}$ = m × v = 250.0 × v = -20·i + 130·j

∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j

The final velocity of the four disks after collision, v = -0.08·i + 0.52·j

The magnitude of the final velocity, $\left | v \right |$ = √((-0.08)² + (0.52)²) ≈ 0.526

$\left | v \right |$ ≈ 0.526 m/s

The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°

The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South

4 0

3 years ago

What is the difference between displacement and distance travelled

IrinaK [193]

Displacement in Space
It is the length of a body's real route. It is the shortest distance between the body's final and beginning positions.
It's a number with a scalar value. It's a quantity with a vector.
It can't possibly be negative. It might be a negative number, a zero number, or a positive number.

8 0

2 years ago

Read 2 more answers

Professional baseball pitchers deliver pitches that can reach the blazing speed of 100 mph (miles per hour). A local team has dr

maria [59]

Answer: 132.02 J

Explanation:

By definition, the kinetic energy is written as follows:

KE = 1/2 m v²

In our question, we know from the question, the following information:

m = 0.1434 Kg

v= 42.91 m/s

Replacing in the equation for KE, we have:

KE = 1/2 . 0.1434 Kg. (42.91)² m²/s² ⇒ KE = 132.02 N. m = 132.02 J

5 0

3 years ago