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ladessa [460]
3 years ago
6

Ammonia at 10◦c with a mass of 10 kg is in a piston/cylinder assembly with an initial volume of 1 m3. the piston initially resti

ng on the stops has a mass such that a pressure of 900 kpa will float it. now the ammonia is slowly heated to 50◦c. find the final pressure and volume.
Physics
1 answer:
jeyben [28]3 years ago
6 0

Here mass is floating on the piston at equilibrium

So it will have constant pressure always remains constant

So final pressure is same as initial pressure = 900 kPa

now we can say

\frac{V_1}{V_2} = \frac{T_1}{T_2}

\frac{1}{V_2} = \frac{273+10}{273+50}

V_2 = 1.14 m^3

so final pressure is 900 kPa and final volume is 1.14 m^3

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Russia shut off the nord stream pipeline that supplies which nation with natural gas?.
Katyanochek1 [597]

Russia shut off the Nord Stream pipeline that supplies natural gas to Germany.

What is the Nord Stream pipeline?

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5 0
2 years ago
Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point,F⃗ 1F→1F_1_vec has a magnitude of 8.80 NN and is directed at an an
castortr0y [4]

Answer:

  • Fx = -9.15 N
  • Fy = 1.72 N
  • F∠γ ≈ 9.31∠-10.6°

Explanation:

You apparently want the sum of forces ...

  F = 8.80∠-56° +7.00∠52.8°

Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

  f∠α = (-f·cos(α), -f·sin(α))

This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.

  = -8.80(cos(-56°), sin(-56°)) -7.00(cos(52.8°), sin(52.8°))

  ≈ (-4.92090, 7.29553) +(-4.23219, -5.57571)

  ≈ (-9.15309, 1.71982)

The resultant component forces are ...

  • Fx = -9.15 N
  • Fy = 1.72 N

Then the magnitude and direction of the resultant are

  F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)

  F∠γ ≈ 9.31∠-10.6°

4 0
3 years ago
The respiratory system - 2/3
stepan [7]

The answers to the respiratory questions are listed below:

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<h3>Meaning of a respiratory system</h3>

A respiratory system is a biological system found in both plants and animals, which includes organs and structures used for exchanging gas between the organisms and its environments.

A respiratory system is a network or chain or organs and tissues that enables breathing.

In conclusion, the respiratory system is one that is very important to understand.

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3 0
2 years ago
bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving -1.72 m/s. what is the veloc
USPshnik [31]

Answer:

The final velocity of the car A is -1.053 m/s.

Explanation:

For an elastic collision both the kinetic energy and the momentum of the system are conserved.

Let us call

m_A = mass of car A;

v_{A1} = the initial velocity of car A;

v_{A2} = the final velocity of car A;

and

m_B = mass of car B;

v_{B1} = the initial velocity of car B;

v_{B2} = the final velocity of car B.

Then, the law of conservation of momentum demands that

m_Av_{A1}+m_Bv_{B1} =m_Av_{A2}+m_Bv_{B2}

And the conservation of kinetic energy says that

\dfrac{1}{2} m_Av_{A1}^2+\dfrac{1}{2}m_Bv_{B1}^2=\dfrac{1}{2}m_Av_{A2}^2+\dfrac{1}{2}m_Bv_{B2}^2

These two equations are solved for final velocities  v_{A2} and v_{B2} to give

$v_{A2} =\frac{m_A-m_B}{m_A+m_B} v_{A1}+\frac{2m_B}{m_A+m_B} v_{B1}$

$v_{B2} =\frac{2m_A}{m_A+m_B} v_{A1}+\frac{m_B-m_A}{m_A+m_B} v_{B1}$

by putting in the numerical values of the variables we get

$v_{A2} =\frac{281-209}{281+209} (2.82)+\frac{2*209}{281+209} (-1.72)$

\boxed{v_{A2} = -1.05m/s}

and

$v_{B2} =\frac{2*281}{281+209} (2.82)+\frac{209-281}{281+209} (-1.72)$

\boxed{v_{B2} = 3.49m/s}

Thus, the final velocity of the car A is -1.053 m/s and of car B is 3.49 m/s.

4 0
3 years ago
In the image, the net force is _______.
Sveta_85 [38]

Your correct answer would be 0 N

The forces are pulling in opposite directions, therefore they cancel each other out.

Hope that helps!!

:)

4 0
3 years ago
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