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ladessa [460]
3 years ago
6

Ammonia at 10◦c with a mass of 10 kg is in a piston/cylinder assembly with an initial volume of 1 m3. the piston initially resti

ng on the stops has a mass such that a pressure of 900 kpa will float it. now the ammonia is slowly heated to 50◦c. find the final pressure and volume.
Physics
1 answer:
jeyben [28]3 years ago
6 0

Here mass is floating on the piston at equilibrium

So it will have constant pressure always remains constant

So final pressure is same as initial pressure = 900 kPa

now we can say

\frac{V_1}{V_2} = \frac{T_1}{T_2}

\frac{1}{V_2} = \frac{273+10}{273+50}

V_2 = 1.14 m^3

so final pressure is 900 kPa and final volume is 1.14 m^3

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FromTheMoon [43]
Force = Mass x Acceleration -> Acceleration = Force/Mass:
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4 0
4 years ago
Two uniform bars of the same dimensions are constructed from the same material. One bar has five evenly spaced holes through it
Elan Coil [88]

Solution :

The angular acceleration, $\alpha$ is obtained from the equation of the $\text{Newton's second law}$ of rotational motion,

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or $\tau = I \times \alpha$

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Thus, $\alpha=\frac{(F\times d)}{I}$

Now if the force and the moment arm distance are constant, then the \text{angular acceleration is inversely proportional to the moment of inertia.}

That is when, F = d = constant, then  $\alpha \propto \frac{1}{I}$ .

Thus, moment of inertia, I is proportional to mass of the bar.

The mass is less for the bar in case (1) in comparison with that with the bar in case (2) due to the holes that is made in the bar.

Therefore, the bar in case (1), has less moment of inertia and a greater angular acceleration.

6 0
3 years ago
Which accounts for an increase in the temperature of a gas that is kept a constant volume
oksian1 [2.3K]

Answer:

An increase in pressure

Explanation:

The ideal gas law states that:

pV=nRT

where

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V is the volume

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T is the temperature of the gas

in the equation, n and R are constant. For a gas kept at constant volume, V is constant as well. Therefore, from the formula we see that if the temperature (T) is increase, the pressure (p) must increase as well.

7 0
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How long does it take a bird to fly 2.5 km if a bird can fly 23km/h?
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Time = Distance / speed

Time =  2.5 km / 23 km/h

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6 0
4 years ago
A weight of 200 n is hung from a spring with a spring constant of 2500 n/m and lowered slowly. How much will the spring stretch?
melisa1 [442]

The length by which the spring got stretched will be 0.08 m. The force is directly propotional to the distance by which the spring stretched.

<h3>What is spring force?</h3>

The force required to extend or compress a spring by some distance scales linearly with respect to that distance is known as the spring force. Its formula is

F = kx

The given data in the problem is;

F is the spring force =200

K is the spring constant= 2500 N/m

x is the length by which spring got stretched =?

The stretch of the spring is found as;

\rm F=kx \\\\ x = \frac{F}{k} \\\\\ x= \frac{200}{2500} \\\\ x=0.08 \ m

Hence the length by which the spring got stretched will be 0.08 m.

To learn more about the spring force refer to the link;

brainly.com/question/4291098

#SPJ4

8 0
3 years ago
Read 2 more answers
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