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ladessa [460]
3 years ago
6

Ammonia at 10◦c with a mass of 10 kg is in a piston/cylinder assembly with an initial volume of 1 m3. the piston initially resti

ng on the stops has a mass such that a pressure of 900 kpa will float it. now the ammonia is slowly heated to 50◦c. find the final pressure and volume.
Physics
1 answer:
jeyben [28]3 years ago
6 0

Here mass is floating on the piston at equilibrium

So it will have constant pressure always remains constant

So final pressure is same as initial pressure = 900 kPa

now we can say

\frac{V_1}{V_2} = \frac{T_1}{T_2}

\frac{1}{V_2} = \frac{273+10}{273+50}

V_2 = 1.14 m^3

so final pressure is 900 kPa and final volume is 1.14 m^3

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almond37 [142]

Answer:

3688 km/h

Explanation:

Given:-

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Solution:-

- Consider the space vehicle as a system that detaches itself into two parts ( command and motor ). We will assume that the gravitational pull due to Earth on the space vehicle is negligible. With that assumption we have our system in isolation. We will apply the principle of conservation of linear momentum on the system as follows:

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                                       Pi = Pf

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Where,

                  M = m + 4m = 5m

                  vc_e = Velocity of command relative to earth

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- We will develop a relation of velocities of command and motor in the frame of earth as follows:

                  vm_e =  v_c/m + vc_e        

- Substituting (vm_e) from Equation 2 into Equation 1, we have:

                  5m*vs_e = m*vc_e + 4m*(v_c/m + vc_e)

                  5m*vs_e = 5m*vc_e + 4m*(v_c/m)

- Solve for vc_e:

                  5m*vs_e -  4m*(v_c/m) = 5m*vc_e

                   vs_e - 0.8*(v_c/m) = vc_e

- Plug in values and evaluate vc_e:

                  vc_e = 3760 - 0.8*(90)

                  vc_e = 3,688 km/h

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<u>Answer:</u>

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