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Anna71 [15]
3 years ago
6

Which of the following are true statements about the electric field? a. A moving charge produces a magnet anomaly. b. The electr

ic field points towards a negative charge and away from a positive charge. c. The direction of the electric field is the direction of acceleration of a positive test charge. d. The electric field is a charge-specific force field independent of any test charge. e. Equipotential lines imply magnitude and direction of the electric field. f. The electric field is a vector field that is found by taking the gradient of the negative potential. g. The electric field inside a spherical conducting shell in 3D is zero. h. If the electric field inside a conductor is nonzero, charges must not be moving; that is, there is a zero current. i. No electric field exists between the plates of a charged capacitor. j. The electric lines of force indicate the vector force experienced by a positive test charge released at a particular point.
Physics
1 answer:
mars1129 [50]3 years ago
4 0

Answer:

a,b,c,d,,f, g, j

Explanation:

e) equipotential lines are lines connecting points of equal potential

h) electric field inside the conductor is non-zero even when there is net movement of charge or non-zero current.

i) capacitors' plates are charged and an electric field exists between the plates.

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anyanavicka [17]

Answer:

Fc = 89.67N

Explanation:

Since the rope is unstretchable, the total length will always be 34m.

From the attached diagram, you can see that we can calculate the new separation distance from the tree and the stucked car H as follows:

L1+L2=34m

L1^2=L2^2=L^2=2^2+(H/2)^2  Replacing this value in the previous equation:

\sqrt{2^2+H^2/4}+ \sqrt{2^2+H^2/4}=34  Solving for H:

H=\sqrt{52}

We can now, calculate the angle between L1 and the 2m segment:

\alpha = atan(\frac{H/2}{2})=60.98°

If we make a sum of forces in the midpoint of the rope we get:

-2*T*cos(\alpha ) + F = 0  where T is the tension on the rope and F is the exerted force of 87N.

Solving for T, we get the tension on the rope which is equal to the force exerted on the car:

T=Fc=\frac{F}{2*cos(\alpha) } = 89.67N

7 0
3 years ago
A circus performer on a pair of stilts exerts a pressure of 32 kPa on the ground. If the performer stands on one stilt, what pre
Agata [3.3K]

Answer:

64 kPa

Explanation:

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p=\frac{F}{A}

where

p is the pressure

F is the force

A is the area on which the force is exerted

In this problem, let's call:

F = the weight of the performer, which is the force

A = the area of 1 stilt

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p=\frac{F}{2A}=32 kPa (1)

Later, he stands on one stilt only. The force exerted is still the same (his weight), however, the area is now reduced to A; therefore, the new pressure is

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4 years ago
Cart 1 of mass m is traveling with speed 2vo in the +x-direction when it has an elastic collision with cart 2 of
iogann1982 [59]

Answer:

Explanation:

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Recall the definitions of

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Then

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and

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