Question

A particle with a mass of 0.01 kg and a net charge of -0.05 C accelerates from rest through a uniform electric field. If the strength of the field is 2000 V/C, what is the speed of the particle after traveling for 0.5 m?

Answer 1

Answer:

The speed of the particle after travelling for 0.5 m is 100 m/s.                            

Explanation:

It is given that,

Mass of the particle, m = 0.01 kg

Net charge on the particle, q = -0.05 C  

Electric field strength, E = 2000 V/C

Distance travelled by the particle, d = 0.5 m

The work done due to motion of the particle is balanced by the change in kinetic energy as :

$Fd=\dfrac{1}{2}mv^2$

v is the speed of the particle

F is the electric force

$qEd=\dfrac{1}{2}mv^2$

$v=\sqrt{\dfrac{2qEd}{m}}$

$v=\sqrt{\dfrac{2\times 0.05\times 2000\times 0.5}{0.01}}$

v = 100 m/s

So, the speed of the particle after travelling for 0.5 m is 100 m/s. Hence, this is the required solution.