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sergeinik [125]
2 years ago
13

2)A relatively unreactive metal that is yellow colored.

Chemistry
1 answer:
Vlad1618 [11]2 years ago
3 0

I think we're in the same class lol

1. Sodium

2. Gold

3.  Helium

4. Sulfur

5. Magnesium

6. Cesium.

7. Silicon

8. fluorine

9. Nickel

10. Magnesium

11. Tungsten

12. hydrogen

13. Calcium

I did my best, here's my answers. Enjoy.

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Answer:

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3 years ago
Under what environmental conditions are you most likely to generate static electricity?
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If it is a really humid warm day, have you ever noticed that's when all electrical storms occur
4 0
3 years ago
Change the bond between the two carbon atoms in each molecule to a double or triple bond as needed to complete the structure. If
Georgia [21]

Answer:

Your question is complex, because I think you wrote it wrong.

Although in front of this what I can help you is that the carbons are associated between a single, double or triple union.

This depends on whether they are attached to more or less carbons or hydrogens, the carbons have the possibility of joining 4 radicals, both other carbons and hydrogens.

Simple junctions talks about compound organisms called ALKANS.

The double unions, in organic these compounds are called as ALQUENOS.

And as for the tertiary unions, the organic chemistry names them as ALQUINOS.

These compounds that we write, a simple union, the less energy, the less this union, that is why the triple bond is the one that contains the most energy when breaking or destroying it in a reaction.

Explanation:

In a chemical compound the change of these unions if we modified them we would generate changes even in the classifications naming them as well as different compounds and not only that until they change their properties

6 0
3 years ago
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musickatia [10]

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Explanation:

3 0
3 years ago
Lead can be prepared from galena [lead(II) sulfide] by first roasting the galena in oxygen gas to form lead(II) oxide and sulfur
Vesna [10]

Answer:

a) Step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)

Step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)

b) The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

Explanation:

a)

Galena = PbS

Lead(II) oxide = PbO

Sulfur dioxide = SO_2

Step 1:

Roasting the galena in oxygen gas to form lead(II) oxide and sulfur dioxide.

Balanced equation of step 1:

2PbS(g)+3O_2(g)\overset{roasting}\rightarrow 2PbO(s)+2SO_2(g)..[1]

Step 2:

Heating the metal oxide with more galena forms the molten metal and more sulfur dioxide.

Balanced equation of step 2:

2PbO(s)+PbS(s)\overset{\Delta }\rightarrow 3Pb(l)+SO_2(g)..[2]

b)

For over all reaction add [1] and [2]. The overall balanced reaction for given process is ;

3PbS(s)+3O_2(g)\rightarrow 3Pb(l)+3SO_2(g)

5 0
3 years ago
Read 2 more answers
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