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Marysya12 [62]
3 years ago
5

1. How many grams would 8.1 x 1021 molecules of sucrose (C12H22011) weigh?

Chemistry
1 answer:
Nimfa-mama [501]3 years ago
7 0

Answer:

Mass = 4.6 g

Explanation:

Given data:

Number of molecules of sucrose = 8.1 ×10²¹ molecules

Mass of sucrose = ?

Solution:

First of all we will calculate the number of moles by using Avogadro number.

1 mole × 8.1 ×10²¹ molecules / 6.022×10²³ molecules

1.35 × 10⁻² mol

Mass of sucrose:

Mass = number of moles × molar mass

Molar mass = 342.3 g/mol

Mass = 1.35 × 10⁻² mol ×342.3 g/mol

Mass = 462.1  × 10⁻² g

Mass = 4.6 g

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False,
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Which of the following should
Sergeu [11.5K]

Answer:

warm water holds the least amount of dissolved oxygen, so I would assume the answer would be D. a small pond could heat up easily. in addition, the water is calm and not moving in a pond

4 0
3 years ago
Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )
Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol

b) To calculate the constant we have the following expression:

lnK=-\frac{deltaG_{rxn} }{RT}

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066

c) The equilibrium pressure of O₂ over M is:

K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm

3 0
3 years ago
"what is the probability of finding an electron within one bohr radius of the nucleus"
Katena32 [7]
Your answer is going to be b
6 0
3 years ago
What volume of carbon dioxide (CO2) will be produced if 2.90 moles of it on (Fe) is produced?
dolphi86 [110]

Answer:

= 97.44 Liters at S.T.P

Explanation:

The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation;

Fe2O3(s)+ 3CO(g) → 3CO2(g) + 2Fe(s)

From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.

Therefore; Mole ratio of Iron : Carbon dioxide is 2:3

Thus; Moles of Carbon dioxide = (2.9/2)×3

                                                   = 4.35 moles

But; 1 mole of CO2 at s.t.p occupies 22.4 liters

Therefore;

Mass of CO2 = 22.4 × 4.35 Moles

                     = 97.44 L

6 0
3 years ago
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