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Advocard [28]
3 years ago
11

1. Rank the following solutions in order of increasing

Chemistry
1 answer:
babunello [35]3 years ago
8 0

The order of the solutions from lowest to highest concentration : A, B, C

<h3>Further explanation</h3>

Given

the following solutions

Required

order of increasing  concentration

Solution

Molarity shows the number of moles of solute in every 1 liter of solution.

\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}

Solution A : 0.5 moles : 2 L solution = 0.25 M

Solution B : 1 moles : 3 L solution = 0.33 M

Solution C : 1.5 moles : 4 L solution = 0.375 M

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An FAS-DPD titration is as simple as a test for total alkalinity or calcium hardness. A buffered DPD indicator powder is added to a water sample and reacts with chlorine to produce the pink color characteristic of the standard DPD test.

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Endocytosis is a type of bulk transport which involves the movement of large particles through the membrane in and out
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How many levels will argon have?
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They have about 4 or 6
7 0
3 years ago
At a certain temperature the rate of this reaction is second order in NH4OH with a rate constant of 34.1 M^-1s^-1: Suppose a ves
Tom [10]

Answer:

Time = 0.929s = 0.93s (2 s.f)

Explanation:

Rate constant, k = 34.1 M^-1s^-1

Initial Concentration, [A]o = 0.100M

Time = ?

Final Concentration [A] = 0.0240M

The parameters are represented in the following equation as;

1/[A] = kt + 1/[A]o

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kt = 1/0.0240 - 1/0.1

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5 0
3 years ago
If the sample has a total mass of 5.76 g and contains 1.79 g k, what are the percentages of kbr and ki in the sample by mass
Luden [163]

The percentages of KBr and KI  in the sample by mass is 80.68 and 19.32 % respectively.

<h3>What is Molar Mass ?</h3>

Molar mass is defined as the mass contained in 1 mole of sample.

It is given that

the sample has a total mass of 5.76 g contains KBr and KI

and contains 1.79 gm of K is present

what is the percentage of KBr and KI in the sample

Molecular weight of K = 39

Molecular weight of Br = 79.9

Molecular weight of I = 126.9

In KBr the mass percentage of K is 39/(39+79.9) = 32.89%

In KI the mass percentage of K is 39/(39+126.9) = 23.5%

Let the mass of KBr present in the sample is x

K will be 0.3289 x

and let the mass of KI present be y

K will be 0.235y

x +y =5.76

0.3289x+0.235y = 1.79

0.0939y = 0.1045

y = 1.1125 gm

x = 5.76-1.1125

x = 4.6475 gm

% of KBr = (4.6475/5.76  )*100 = 80.68 %

% of KI = (1.1125/5.76) *100 = 19.32%

To know more about Molar Mass

brainly.com/question/12127540

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8 0
2 years ago
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