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butalik [34]
3 years ago
6

Part G

Chemistry
1 answer:
Reil [10]3 years ago
6 0

The molecule ammonium lauryl sulfate is a detergent because of its hydrophobic tail and a hydrophilic head which are responsible for its cleansing action.

<h3>Properties of ammonium lauryl sulfate</h3>

Though not shown, I presume that the property labelled as C must have to do with the cleasing action of the molecule ammonium lauryl sulfate.

The substance has a hydrophobic tail and a hydrophilic head which enables it to form miscles and these are the responsible for the cleansing action of the ammonium lauryl sulfate molecule.

Learn more about ammonium lauryl sulfate: brainly.com/question/16483020

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Convert 6.35 grams of aluminum sulfate to moles​
vampirchik [111]

Answer:

There are 0.0186 moles of formula units in 6.35 grams of aluminum sulfate \rm Al_2(SO_4)_3.

Explanation:

What's the empirical formula of aluminum sulfate?

Sulfate is an anion with a charge of -2 per ion. When sulfate ions are bonded to metals, the compound is likely ionic.

Aluminum is a group III metal. Its ions tend to carry a charge of +3 per ion.

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  • Three sulfate ions \rm {SO_4}^{2-} will give a charge of -6.
  • Two aluminum ions \rm Al^{3+} will give a charge of +6.

Pairing three \rm {SO_4}^{2-} ions with two \rm Al^{3+} will balance the charge. Hence the empirical formula: \rm Al_2(SO_4)_3.

What's the mass of one mole of aluminum sulfate? In other words, what's the formula mass of \rm Al_2(SO_4)_3?

Refer to a modern periodic table for relative atomic mass data:

  • Al: 26.982;
  • S: 32.06;
  • O: 15.999.

There are

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  • three S, and
  • twelve O

in one formula unit of \rm Al_2(SO_4)_3.

Hence the formula mass of \rm Al_2(SO_4)_3:

\underbrace{2\times 26.982}_{\rm Al} + \underbrace{3\times 32.06}_{\rm S} + \underbrace{12\times 15.999}_{\rm O} = \rm 342.132\;g\cdot mol^{-1}.

How many moles of formula units in 6.35 grams of \rm Al_2(SO_4)_3?

\displaystyle n = \frac{m}{M} = \rm \frac{6.35\;g}{342.132\;g\cdot mol^{-1}} = 0.0186\;mol.

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