A 1-kilogram turtle crawls in a straight line at a speed of 0.01 m/sec what is the turtles momentum

A wave has a wave length of 20mm and a frequency of 5 hertz. What is the speed?

zmey [24]

Speed = (wavelength) x (frequency

Speed = (.020 m) x (5 / sec)

Speed = 0.1 m/s

7 0

3 years ago

Driving your Ferrari through the Italian countryside at a speedy 88 m/s, you approach an opera diva singing a high C (1,046 Hz).

MrRissso [65]

Answer:

You will hear the note E₆

Explanation:

We know that:

Your speed = 88m/s

Original frequency = 1,046 Hz

Sound speed = 340 m/s

The Doppler effect says that:

$f' = \frac{v \pm v0 }{v \mp vs}*f$

Where:

f = original frequency

f' = new frequency

v = velocity of the sound wave

v0 = your velocity

vs = velocity of the source, in this case, the source is the diva, we assume that she does not move, so vs = 0.

Replacing the values that we know in the equation we have:

$f' = \frac{340 m/s + 88m/s}{340 m/s} *1,046 Hz = 1,316.73 Hz$

This frequency is close to the note E₆ (1,318.5 Hz)

7 0

3 years ago

Calculate the work done by a force of 30 N in lifting a load of 2 kg to a height of 10 m (g = 10 m/s2)

Mars2501 [29]

Answer:

300 J

Explanation:

Given :

Applied force = 30 N
Mass = 2 kg
Height = 10 m
g = 10 m/s²

Work done by the force :

Work done = Force x Displacement
Work done = mg x h
Work done = 30 N x 10 m
Work done = 300 J

Note :

What you have calculated is the work done by gravitational force on the object (that too, incorrectly)
But in the end, it asks for work done by the force of 30N
Hence, the given answer ~

3 0

3 years ago

ANSWER PLS THIS WILL BRING MY GRADE REALLY HIGH UP Which of the following is not a compound

stepladder [879]

3 rd one because I had this on my test

4 0

4 years ago

Read 2 more answers

michael kicks a ball at an angle if 36* horizontal. its initial velocity is 46 m/s. Find the maximum height it can reach, total

MAVERICK [17]

(a) At its maximum height, the ball's vertical velocity is 0. Recall that

${v_y}^2-{v_{0y}}^2=2a_y\Delta y$

Then at the maximum height $\Delta y=y_{\mathrm{max}}$ , we have

$-\left(\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ\right)^2=2\left(-9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)y_{\mathrm{max}}$

$\implies y_{\mathrm{max}}=37\,\mathrm m$

(b) The time the ball spends in the air is twice the time it takes for the ball to reach its maximum height. The ball's vertical velocity is

$v_y=v_{0y}+a_yt$

and at its maximum height, $v_y=0$ so that

$0=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\sin36^\circ+\left(-9.8\,\dfrac{\mathrm m}{\mathrm s}\right)t$

$\implies t=2.8\,\mathrm s$

which would mean the ball spends a total of about 5.6 seconds in the air.

(c) The ball's horizontal position in the air is given by

$x=v_{0x}t$

so that after 5.6 seconds, it will have traversed a displacement of

$x=\left(46\,\dfrac{\mathrm m}{\mathrm s}\right)\cos36^\circ(5.6\,\mathrm s)$

$\implies x=180\,\mathrm m$

3 0

3 years ago