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STALIN [3.7K]
3 years ago
9

Explain Newton’s 3 laws of motion by using the example of a rollercoaster?

Physics
1 answer:
ivolga24 [154]3 years ago
5 0

Newton's First law states the Law of Inertia. The Law of Inertia says that an object at rest must stay at rest unless an applied force is acted upon it. Roller coasters run by this law, they must be pulled by a motor to get started. ... At ride will continue until another opposite force is applied to the ride, the breaks.

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Transformation 3 should Tracy removed from the list. Chemical energy transforms into gravitational potential energy.

<h3> What is the law of conservation of energy?</h3>

According to the Law of Conservation of Energy, energy can neither be created nor destroyed, but it can be transferred from one form to another.

The total energy is the sum of all the energies present in the system. The potential energy in a system is due to its position in the system.

Transformations that occur as an engine runs to power a car is;

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Hence, transformation 3 should Tracy removed from the list.

To learn more about the law of conservation of energy, refer to brainly.com/question/2137260.

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2 years ago
Frank and Lisa are analyzing the chart, which shows the speed at which light travels through different media. Frank says that li
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The correct answer is
c) Neither person is correct because light does not change frequency when it travels through different media

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Describe the shapes of a concave lens and a convex lens
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A flea jumps by exerting a force of 1.09 ✕ 10−5 N straight down on the ground. A breeze blowing on the flea parallel to the grou
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Answer:

a= 17.877 m/s² : Magnitude of the acceleration of the flea

β = 88.21°  :  Direction  of the acceleration of the flea

Explanation:

Conceptual analysis

We apply Newton's second law:

∑F = m*a (Formula 1)

∑F : algebraic sum of the forces in Newton (N)

m : mass in kilograms (kg)

a : acceleration in meters over second square (m/s²)

Problem development

Look at the flea free body diagram in the attached graphic

The acceleration is presented in the direction of the resultant force (R) applied over the flea .

R= \sqrt{(F_{x})^{2} + (F_{y})^{2} }

R= \sqrt{(10.9)^{2}+(0.340)^{2}  } *10^{-6} N

R= 10.905*10⁻⁶ N

We apply the formula (1) to calculate the magnitude of the acceleration of the flea

∑F = m*a   m = 6.1 * 10⁻⁷ kg

R = m*a

a= R/m

a= (10.905*10⁻⁶) /  (6.1 * 10⁻⁷ )

a= 17.877 m/s²

β: Direction and magnitude of the acceleration of the flea

\beta = tan^{-1} (\frac{F_{y} }{F_{x} } )

\beta = tan^{-1} (\frac{10.9*10^{-6} }{0.340*10^{-6} } )

β = 88.21°

5 0
4 years ago
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