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stiks02 [169]
3 years ago
11

Fahd is trying to write a focused scientific question. He writes, “Does the material something is made of affect its density?” H

ow could Fahd’s question best be rewritten? How does changing an object’s material change its density? How are material and density related? Does changing the density of an object change its material? What affects density?
Physics
2 answers:
natta225 [31]3 years ago
6 0

 Explanation :

Fahd is trying to write a focused scientific question. He write the question as " Does the material something is made of affect its density? "

Density is the ratio of mass and the volume of an object. Density depends only on mass and volume of the substance.

This question could be rewritten as :

How does changing an object’s material change its density?

garik1379 [7]3 years ago
5 0

Answer:

Does the material's characterisitcs/composition affect its density,

Every material has unique mass to volume ratio. Therefore changing a material of an object changes its density or we can say mass to volume ratio

Density= mass of material/volume of material

Not always

mass to volume ratio, pressure and temperature

Explanation:

"Something is made of" refers to composition of a material. The composition of a material defines it characteristics so Fahd's statement can be re-written as: " Does the material's characterisitcs/composition affect its density".

Density is defined as ratio of mass of a material to its volume at a specific temperature and pressure.It is a physical property of a material. It is affected by temperature and pressure. Temperature affects the volume hence the density of the material.  Pressure also afects the volume of the material, hence its density. Each material has unique value of density at a particular temperature and pressue

If an object is changed by changing material at a particular temperature and pressue, that is changing the characteristics or composition of material, then the object's density also changes.

Density of material is changed by changing its mass to volume ratio or by changing its temperature or by changing its pressure, then density of material changes.

From above description it can be inferred that a material's composition or chemial characteristics may remain unchanged, if density changes by changing pressure or temperature of the material

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Answer:

A)   F_g = 4.05 10⁻⁴⁷ N, B)   F_e = 9.2 10⁻⁸N, C)    \frac{F_e}{F_g} = 2.3 10³⁹

Explanation:

A) It is asked to find the force of attraction due to the masses of the particles

Let's use the law of universal attraction

            F = G \frac{m_1m_2}{r^2}

let's calculate

            F = 6.67 \ 10^{-11} \ \frac{9.1 \ 10^{-31} \ 1.67 \ 10 ^{-27} }{(5 \ 10^{-11})^2 }

            F_g = 4.05 10⁻⁴⁷ N

B) in this part it is asked to calculate the electric force

Let's use Coulomb's law

            F = k \  \frac{q_1q_2}{r^2}

let's calculate

            F = 9 \ 10^9 \  \frac{(1.6 \ 10^{-19} )^2}{(5 \ 10^{-11})^2}

             F_e = 9.2 10⁻⁸N

C) It is asked to find the relationship between these forces

        \frac{F_e}{F_g} = \frac{9.2 \ 10^{-8} }{4.05 \ 10^{-47} }

        = 2.3 10³⁹

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A projectile has an initial horizontal velocity of 15 meters per second and an initial vertical velocity of 25 meters per second
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Answer:

75 m

Explanation:

The horizontal motion of the projectile is a uniform motion with constant speed, since there are no forces acting along the horizontal direction (if we neglect air resistance), so the horizontal acceleration is zero.

The horizontal component of the velocity of the projectile is

v_x = 15 m/s

and it is constant during the motion;

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Therefore, we can apply the formula of the uniform motion to find the horizontal displacement of the projectile:

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3 years ago
2. A 2000 kg car with speed 12.0 m/s hits a tree. The tree does not move or
krek1111 [17]

a) The work done by the tree is -1.44\cdot 10^5 J

b) The amount of force applied is 2880 N

Explanation:

a)

According to the work-energy theorem, the work done on the car is equal to the change in kinetic energy of the car. Therefore, we can write:

W=K_f - K_i = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

W is the work done on the car

m is the mass of the car

u is its initial speed

v is its final speed

For the car in this problem, we have:

m = 2000 kg

u = 12.0 m/s

v = 0 (since the car comes to a stop, after the crash)

Therefore, the work done by the tree on the car is:

W=0-\frac{1}{2}(2000)(12.0)^2=-1.44\cdot 10^5 J

The work is negative because it is done in the direction opposite to the direction of motion of the car.

b)

The work done by the tree on the car can also be rewritten as

W=Fd

where

F is the force applied on the car

d is the displacement of the car during the collision

In this situation, we have:

W=-1.44\cdot 10^5 J is the work done

d=50.0 cm = 0.50 m is the displacement of the car during the collision

Solving the equation for F, we find the force exerted by the tree on the car:

F=\frac{W}{d}=\frac{-1.44\cdot 10^5 J}{0.50}=-2880 N

Where the negative sign means the force is applied opposite to the direction of motion of the car. Therefore, the magnitude of the force applied is 2880 N.

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brainly.com/question/6763771

brainly.com/question/6443626

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