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stiks02 [169]
2 years ago
11

Fahd is trying to write a focused scientific question. He writes, “Does the material something is made of affect its density?” H

ow could Fahd’s question best be rewritten? How does changing an object’s material change its density? How are material and density related? Does changing the density of an object change its material? What affects density?
Physics
2 answers:
natta225 [31]2 years ago
6 0

 Explanation :

Fahd is trying to write a focused scientific question. He write the question as " Does the material something is made of affect its density? "

Density is the ratio of mass and the volume of an object. Density depends only on mass and volume of the substance.

This question could be rewritten as :

How does changing an object’s material change its density?

garik1379 [7]2 years ago
5 0

Answer:

Does the material's characterisitcs/composition affect its density,

Every material has unique mass to volume ratio. Therefore changing a material of an object changes its density or we can say mass to volume ratio

Density= mass of material/volume of material

Not always

mass to volume ratio, pressure and temperature

Explanation:

"Something is made of" refers to composition of a material. The composition of a material defines it characteristics so Fahd's statement can be re-written as: " Does the material's characterisitcs/composition affect its density".

Density is defined as ratio of mass of a material to its volume at a specific temperature and pressure.It is a physical property of a material. It is affected by temperature and pressure. Temperature affects the volume hence the density of the material.  Pressure also afects the volume of the material, hence its density. Each material has unique value of density at a particular temperature and pressue

If an object is changed by changing material at a particular temperature and pressue, that is changing the characteristics or composition of material, then the object's density also changes.

Density of material is changed by changing its mass to volume ratio or by changing its temperature or by changing its pressure, then density of material changes.

From above description it can be inferred that a material's composition or chemial characteristics may remain unchanged, if density changes by changing pressure or temperature of the material

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Answer:

Explanation:

Given

\mu =0.14 Pa.s

Volume Flow rate Q=5.3\times 10^{-5} m^3/s

Length L=37 m

radius r=0.58 cm

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According to Hagen-Poiseuille Equation

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\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}

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3 years ago
An airplane of mass 1.60 ✕ 104 kg is moving at 66.0 m/s. The pilot then increases the engine's thrust to 7.70 ✕ 104 N. The resis
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(a) No, because the mechanical energy is not conserved

Explanation:

The work-energy theorem states that the work done by the engine on the airplane is equal to the gain in kinetic energy of the plane:

W=\Delta K (1)

However, this theorem is only valid if there are no non-conservative forces acting on the plane. However, in this case there is air resistance acting on the plane: this means that the work-energy theorem is no longer valid, because the mechanical energy is not conserved.

Therefore, eq. (1) can be rewritten as

W=\Delta K + E_{lost}

which means that the work done by the engine (W) is used partially to increase the kinetic energy of the airplane (\Delta K) and part is lost because of the air resistance (E_{lost}).

(b) 77.8 m/s

First of all, we need to calculate the net force acting on the plane, which is equal to the difference between the thrust force and the air resistance:

F=7.70\cdot 10^4 N - 5.00 \cdot 10^4 N=2.70\cdot 10^4 N

Now we can calculate the acceleration of the plane, by using Newton's second law:

a=\frac{F}{m}=\frac{2.70\cdot 10^4 N}{1.60\cdot 10^4 kg}=1.69 m/s^2

where m is the mass of the plane.

Finally, we can calculate the final speed of the plane by using the equation:

v^2- u^2 = 2aS

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u=66.0 m/s is the initial velocity

a=1.69 m/s^2 is the acceleration

S=5.00 \cdot 10^2 m is the distance travelled

Solving for v, we find

v=\sqrt{u^2+2aS}=\sqrt{(66.0 m/s)^2+2(1.69 m/s^2)(5.00\cdot 10^2 m)}=77.8 m/s

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