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scoundrel [369]
2 years ago
12

Can someone please answer this, ill give you brainliest Would be very appreciated.

Physics
2 answers:
Evgesh-ka [11]2 years ago
3 0

Answer:

False

Explanation:

Solid water (ice) has a lesser density than liquid water. Hence, the statement is false.

Aleks04 [339]2 years ago
3 0

Answer:

False

Explanation:

Let's know the relationship

  • Density=Mass/Volume

Density is indirectly proportional to volume

If volume is less density is more and if volume is more density is less.

But Density also depends on temperature

Higher the temperature higher the density.

  • Liquid stage of water has higher temperature than solid .

Liquid has higher density than solid .

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If a fish is trying to capture an insect hovering above the surface of the water – how will it jump to catch it? Will it aim abo
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Answer:

It will have aim at a point "below" the insect.

From the insect's point of view, the fish will appear to be shallower than it actually is because a ray of light from the insect to the fish will be bent "towards" the normal when the ray enters the water

5 0
2 years ago
The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge
lesya [120]

Answer:

Loss, \Delta E=-10.63\ J

Explanation:

Given that,

Mass of particle 1, m_1=m =0.66\ kg

Mass of particle 2, m_2=7.4m =4.884\ kg

Speed of particle 1, v_1=2v_o=2\times 6=12\ m/s

Speed of particle 2, v_2=v_o=6\ m/s

To find,

The magnitude of the loss in kinetic energy after the collision.

Solve,

Two particles stick together in case of inelastic collision. Due to this, some of the kinetic energy gets lost.

Applying the conservation of momentum to find the speed of two particles after the collision.

m_1v_1+m_2v_2=(m_1+m_2)V

V=\dfrac{m_1v_1+m_2v_2}{(m_1+m_2)}

V=\dfrac{0.66\times 12+4.884\times 6}{(0.66+4.884)}

V = 6.71 m/s

Initial kinetic energy before the collision,

K_i=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

K_i=\dfrac{1}{2}(0.66\times 12^2+4.884\times 6^2)

K_i=135.43\ J

Final kinetic energy after the collision,

K_f=\dfrac{1}{2}(m_1+m_2)V^2

K_f=\dfrac{1}{2}(0.66+4.884)\times 6.71^2

K_f=124.80\ J

Lost in kinetic energy,

\Delta K=K_f-K_i

\Delta K=124.80-135.43

\Delta E=-10.63\ J

Therefore, the magnitude of the loss in kinetic energy after the collision is 10.63 Joules.

7 0
3 years ago
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Answer:

The rod attracts the ball

Explanation:

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Plzzzz help it for civics
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Answer:

A : the colonists dumped tea in Boston Harbor

6 0
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Radar tells an air traffic controller that a jet is slowing as it nears the airport. Which might represent the jet’s speed
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