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Scorpion4ik [409]
3 years ago
15

How would you expect this object to behave if it starts out not moving? (the object is a circle, and the arrows show forces acti

ng on the object)
A. Move to the right at a constant speed
B. speed up moving to the left
C. speed up moving to the right
D. move to the left at a constant speed


Plz help and explain if you can

Chemistry
2 answers:
Oduvanchick [21]3 years ago
8 0
B.  It would have a net force of 200N to the left. Meaning the the forces are unbalanced and the net force would cause it to accelerate (speed up) in the direction of the net force.
denis23 [38]3 years ago
4 0

Answer:

The answer is B Moving toward the left

Explanation:

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There are two physical properties of minerals that both result in smooth, flat surfaces with specific angles between them. The f
stich3 [128]

Answer:

3. crystal habit and cleavage.

Explanation:

Crystal habit is a distinctive characteristic which is shown in its general shape,  crystallographic forms, how developed each form is.

Cleavage is the ability of a mineral to break in smooth planes parallel to zones of weak bonding. Cleavage in three directions at right angles (90o). Cubic cleavage. Cleavage in three directions not at right angles (120o and 60o).

3 0
3 years ago
Please Help! Thank You
Ivanshal [37]

Explanation:

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2 years ago
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5 0
3 years ago
Read 2 more answers
A mixture of helium, nitrogen, and oxygen has a total pressure of 752 mm Hg. The
NISA [10]

Answer: The partial pressure of oxygen in the mixture is 321 mm Hg

Explanation:

According to Dalton's law, the total pressure is the sum of individual pressures.

p_{total}=p_{He}+p_{N_2}+p_{O_2}

Given : p_{total} = total pressure of gases = 752 mm Hg

p_{He} = partial pressure of Helium = 234 mm Hg

p_{N_2} = partial pressure of nitrogen = 197 mm Hg

p_{O_2} = partial pressure of oxygen = ?

Putting in the values we get:

752mmHg=234mmHg+197mmHg+p_{O_2}

p_{O_2}=321mmHg

The partial pressure of oxygen in the mixture is 321 mm Hg

5 0
3 years ago
How much heat is required to change the temperature of a 15 g aluminum can with 100 g of water from 24.5°C to 55°C?
Assoli18 [71]
Heat capacity of aluminium = 0.900 J/g°C
While heat capacity of water = 4.186 J/g°C
Heat = heat gained by water + heat gained by aluminium 
Heat gained by water = 100 × 4.186 × 30.5 
                                   = 12767.3 Joules
Heat gained by aluminium = 15 × 0.9 × 30.5 
                                          = 411.75 Joules
Heat required = 13179.05 Joules or 13.179 kJoules
3 0
3 years ago
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