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3 years ago

During the bromination of methane the free radical Ch3 is generated

Chemistry

2 answers:

Step2247 [10]3 years ago

3 0

Hfuch j hdhck kxgzj k hzy j.

Masteriza [31]3 years ago

3 0

Answer:

yes

Explanation:

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PLEASE HELP ASAP!!!!! WILL GIVE BRAINLIEST!!!!

Akimi4 [234]

Explanation:

The magnet uses electromagnetic induction meaning it can be readily magnetized and demagnetized (using electricity) when required. When electricity is switched on, it becomes magnetized and lifts an object and when electricity is switched off, it loses magnetism and releases the object.

The magnetic is able to lift heavy objects because it has powerful conductor material (ferromagnetic iron) and the number of electromagnetic coils is many to induce a powerful magnetic force. The electric current, inducing the magnetism, is also powerful.

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3 years ago

Which is the iupac name for no?

pshichka [43]

The IUPAC name of NO is nitric oxide. It is one of the many oxides of nitrogen. It is a colorless gas under standard temperature and pressure. It found great application in the combustion of fossil fuels in power plants. This substance is produced naturally by lightning.

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3 years ago

Read 2 more answers

Explain how natural resources are identified and why natural recourses are in evenly distributed.

mixer [17]

Answer:

Natural resources are not evenly distributed all over the world. Some places are more endowed that others — for instance, some regions have lots of water (and access to ocean and seas). Others have lots of minerals and forestlands. Others have metallic rocks, wildlife, fossil fuels and so on.

Explanation:

3 0

3 years ago

Calculate RMM given Aluminium sulphate given RAM: A1-27; S-32; 0-16

kodGreya [7K]

Answer:

IMISS THE RAGE⁉️⁉️⁉️⁉️⁉️⁉️IMISS THE RAGE⁉️⁉️⁉️⁉️⁉️⁉️IMISS THE RAGE⁉️⁉️⁉️⁉️⁉️⁉️

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2 years ago

An aqueous solution is listed as being 33.8% solute by mass with a density of 1.15 g/mL, the molar mass of the solute is 145.6 g

vodomira [7]

Answer:

A) 2.69 M

B) 0.059

Explanation:

A) We have:

33.8% solute by mass= 33.8 g solute/100 g solution

molarity = mol solute/ 1 L solution

molarity= $\frac{33.8 g solute}{100 g solution}$ x $\frac{1.15 g solution}{1 ml}$ x $\frac{1 mol solute}{145.6 g solute}$ x $\frac{1000 ml}{1 L}$

molarity= 2.69 mol solute/L solution = 2.69 M

B) We know that there are 33.8 g of solute in 100 g of solution.

As the total solution is compounded by solute+solvent (in this case, solvent is water), the mass of water is the difference between the mass of the total solution and the mass of solute:

mass of water= 100 g - 33.8 g = 66.2 g

Now, we calculate the number of mol of both solute and water:

mol solute= 33.8 g solute x $\frac{1 mol solute}{145.6 g}$ = 0.232 mol

mol H20= 66.2 g H₂O x $\frac{1 mol H2O}{18 g}$

Finally, the mol fraction of solute (Xsolute) is calculated as follows:

Xsolute= $\frac{mol solute}{total mol}= \frac{mol solute}{mol solute + mol H2O}=\frac{0.232 mol}{0.232 mol + 3.677 mol}$

Xsolute= 0.059

4 0

2 years ago