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Answer:
F ∪ H = [2, ∞)
F ∩ H = (6, ∞)
Step-by-step explanation:
Graphs of the two sets are shown in the attachment. Set F is shown in red; set H is shown in blue. The solid dot means the point is included in the set, equivalent to a square bracket in interval notation. The open dot means the point is not included in the set, equivalent to a round bracket (parenthesis) in interval notation.
<u>F ∪ H</u>
The union of two sets is the set that contains elements that are members of either set. Here, set F includes all of the elements of set H, so the union of the to sets is simply set F.
F∪H = F = [2, ∞)
__
<u>F ∩ H</u>
The intersection of two sets is the set of elements that are common to both sets. Here, every element of set H is also an element of set F, but not vice versa. So, the intersection of the sets is equivalent to set H.
F∩H = H = (6, ∞)
Answer:
6x + 1
Step-by-step explanation:
Distribute
3 + 2 ( x- 1 ) + 4x
3 + 2x - 2 + 4x
Subtract
3 + 2x - 2 + 4x
1 + 2x + 4x
Like terms
1 + 2x + 4x
1 + 6x
Rearrange
6x + 1
<span>Implement and follow up on the solution. Hope this helps :)</span>
Sin(theta) = 4/5,
We will switch it to formula: