Answer:
10.2 metres
Explanation:
Given that a ball is projected at an initial speed of 20.0 meter per second making an angle of 45.0 with horizontal. What is the maximum height it will reach?
Solution
To get the maximum height, let us use the formula
V^2 = U^2 sin^2ø - 2gH
At maximum height V = 0
U^2 sin^2ø = 2gH
Substitute all the parameters into the formula
20^2 ( sin 45 )^2 = 2 × 9.8 × H
400 × 0.5 = 19.6 H
Make H the subject of formula
H = 200 / 19.6
H = 10.204 metres.
Therefore, the maximum height reached by the projected ball is 10.2 metres.
Distance is how far something moves in a specific amount of time.
It would be C as the law says "<span>Formally stated, </span>Newton's third law<span> is: For every action, there is an equal and opposite reaction. The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object."</span>
<span>#1
“A persons body continuing to move forward even though the car comes to
a sudden stop” Which newtons Law Do they pertain?
A: First Law </span>
<span>#2 “A fighter Pilot Feels Massive Amounts of forcé when his plane turns sharply” Which Newton Law?
A: First Law.
</span><span><span>You were following the
Newton's first law and kept your velocity straight until you departed from linear motion when you turn sharply; you are forced to follow the curve. <span>The
force that the jet exerts on you is called centripetal force and is
suitable for the center of curvature of the forced traveling path.</span></span>
</span><span>#3 “ A Paddle wheel boat pushed on water and the water pushes back causing the boat to move” Which Netwons Law?
C: Third Law</span>
