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artcher [175]
3 years ago
14

How is the acceleration of a car traveling on an elevated air track related to the angle of elevation and the height of elevatio

n?
Physics
1 answer:
vitfil [10]3 years ago
4 0

on a given inclined we know that net force is given by

F_{net} = - mgsin\theta

here we know that

F_{net} = ma

so here we have

ma = - mg sin\theta

a = - gsin\theta

so here acceleration depends directly on angle of inclination

now we also know that if height of the inclined is H and its length is L

then we can write

sin\theta = \frac{H}{L}

so the acceleration is given as

a = - g*\frac{H}{L}

so acceleration also depends directly on height of the inclined plane

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An electric dipole of dipole moment 'p' is placed in the position of stable equilibrium in a uniform field of intensity 'E'. The
larisa86 [58]

Answer:

Torque by electric dipole = pEcos thita

5 0
4 years ago
1 A 75-g ball is projected from a height of 1.6 m with a horizontal velocity of 2 m/s and bounces from a 400-g smooth plate supp
Tanzania [10]

Answer with explanation:

We are given that  

Mass of ball,m_1=75 g=\frac{75}{1000}=0075kg

1 kg=1000 g

Height,h_1=1.6 m

h_2=0.6 m

Horizontal velocity,v_x=2 m/s

Mass of platem_2=400 g=\frac{400}{1000}=0.4 kg

a.Initial velocity of plate,u_2=0

Velocity before impact=u_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 1.6}=5.6m/s

Where g=9.8 m/s^2

Velocity after impact,v_1=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.6}=3.4m/s

According to law of conservation of momentum  

m_1u_1+m_2u_1=-m_1v_1+m_2v_2

Substitute the values  

0.075\times 5.6+0=-0.075\times 3.4+0.4v_2

0.4v_2=0.075\times 5.6+0.075\times 3.4

v_2=\frac{0.075\times 5.6+0.075\times 3.4}{0.4}=1.69 m/s

Velocity of plate=1.69 m/s

b.Initial energy=\frac{1}{2}m_1v^2_x+m_1gh_1=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 1.6=1.326 J

Final energy=\frac{1}{2}m_1v^2_x+m_1gh_2+\frac{1}{2}m_2v^2_2

Final energy=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 0.6+\frac{1}{2}(0.4)(1.69)^2=1.162 J

Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J

6 0
3 years ago
The wheels of a car have radius 12 in. and are rotating at 600 rpm. Find the speed of the car in mi/h.
guajiro [1.7K]

Answer:

21.4 mph

Explanation:

Circumference of tire in FEET   = pi * d =  pi * 1 ft = pi  feet

pi feet  x  600 rot/min  *  60 min /hr  *  1 mile / 5280 feet = 21.4 mph

7 0
1 year ago
4. The Earth is the only planet that contains storms. Tor F 5. Lightning is a form of energy made up of protons that move from c
Mumz [18]

Answer:

4. F

5. F

Explanation:

jupiter constantly has hurricanes and uranus has storms often too.

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6 0
3 years ago
25 Points PLEASE I need Help
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Answer:nah u took my points I take urs

Explanation:

6 0
3 years ago
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