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artcher [175]
3 years ago
14

How is the acceleration of a car traveling on an elevated air track related to the angle of elevation and the height of elevatio

n?
Physics
1 answer:
vitfil [10]3 years ago
4 0

on a given inclined we know that net force is given by

F_{net} = - mgsin\theta

here we know that

F_{net} = ma

so here we have

ma = - mg sin\theta

a = - gsin\theta

so here acceleration depends directly on angle of inclination

now we also know that if height of the inclined is H and its length is L

then we can write

sin\theta = \frac{H}{L}

so the acceleration is given as

a = - g*\frac{H}{L}

so acceleration also depends directly on height of the inclined plane

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NEED HELP ASP<br> WILL GIVE POINTS OR WHATEVER
solniwko [45]

Answer:

you need to multiply the momentum and the mass

8 0
3 years ago
Which technological advance allows scientists to handle these objects enough to feel their properties while still protecting the
muminat
The answer depends heavily on what 'objects' you're talking about.
5 0
4 years ago
Read 2 more answers
considere que o calor específico de um material presente nas cinzas seja c=0,8j/gc. Supondo que esse material entre na turbina a
drek231 [11]

Answer:

3120J

Explanation:

Given parameters:

C  = Specific heat capacity  = 0.8J/g°C

Initial temperature  = 20°C

Mass given   = 5g

Final temperature  = 800°C

Unknown:

Energy given to the mass  = ?

Solution:

To find the energy given to the mass, let us simply use the expression below:

          H   =   m   c   ΔT

H is the unknown, the energy supplied

m is the mass of the substance

c is the specific heat capacity

ΔT is the change in temperature

Input the variables;

            H    = 5  x   0.8    x    (800 - 20)  = 3120J

7 0
3 years ago
You observe that a mass suspended by a spring takes 0.25 s to make a full oscillation. What is the frequency of this oscillation
Katarina [22]

Answer:

Frequency of oscillation, f = 4 Hz

time period, T = 0.25 s

Angular frequency, \omega = 25.13 rad/s

Given:

Time taken to make one oscillation, T = 0.25 s

Solution:

Frequency, f of oscillation is given as the reciprocal of time taken for one oscillation and is given by:

f = \frac{1}{T}

f = \frac{1}{0.25}

Frequency of oscillation, f = 4 Hz

The period of oscillation can be defined as the time taken by the suspended mass for completion of one oscillation.

Therefore, time period, T = 0.25 s

Angular frequency of oscillation is given by:

\omega = 2\pi \times f

\omega = 2\pi \times 4

\omega = 25.13 rad/s

5 0
4 years ago
Suppose a log's mass is 5 kg. After burning, the mass of the ash is 1 kg. explain what May have happened to the other 4 kg.
ladessa [460]

The other 4 kg of mass may have departed the scene
of the fire, in the form of gases and smoke particles.

7 0
3 years ago
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