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3 years ago

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What are factors within a region that affect or limit the physical environment?

2 answers:

Bingel [31]3 years ago

8 0

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What are factors within a region that affect or limit the physical environment?

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Abiotic Factors. The most recognizable limitations to the geographic distribution of a species include insurmountable physical barriers, such as mountains, oceans, rivers, deserts, and, more recently, expansive human development.

NISA [10]3 years ago

6 0

Answer:Some examples of limiting factors are biotic, like food, mates, and competition with other organisms for resources. Others are abiotic, like space, temperature, altitude, and amount of sunlight available in an environment. Limiting factors are usually expressed as a lack of a particular resource.

Explanation:hope this helps you

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If i like a boy and he dont like me what should i do? If we like each other what should i do?

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Answer:

If he doesn't like you then hang out with him more but if he does then try to keep your cool

Explanation:

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3 years ago

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You are standing outside during the daytime. How can you see a blade of grass?

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Answer:

C: Light travels from the Sun to the grass and is then reflected to your eyes.

Explanation:

Our eyes don't produce light but detect light (so answer A is not correct)

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Answer C is the correct one.

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3 years ago

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Which of the circuit diagrams shown in Figure 21-1A is a parallel circuit?

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3 years ago

The magnitude of the gravitational field strength near Earth's surface is represented by

Zanzabum

Answer:

The magnitude of the gravitational field strength near Earth's surface is represented by approximately $9.82\,\frac{m}{s^{2}}$ .

Explanation:

Let be M and m the masses of the planet and a person standing on the surface of the planet, so that M >> m. The attraction force between the planet and the person is represented by the Newton's Law of Gravitation:

$F = G\cdot \frac{M\cdot m}{r^{2}}$

Where:

$M$ - Mass of the planet Earth, measured in kilograms.

$m$ - Mass of the person, measured in kilograms.

$r$ - Radius of the Earth, measured in meters.

$G$ - Gravitational constant, measured in $\frac{m^{3}}{kg\cdot s^{2}}$ .

But also, the magnitude of the gravitational field is given by the definition of weight, that is:

$F = m \cdot g$

Where:

$m$ - Mass of the person, measured in kilograms.

$g$ - Gravity constant, measured in meters per square second.

After comparing this expression with the first one, the following equivalence is found:

$g = \frac{G\cdot M}{r^{2}}$

Given that $G = 6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}}$ , $M = 5.972 \times 10^{24}\,kg$ and $r = 6.371 \times 10^{6}\,m$ , the magnitude of the gravitational field near Earth's surface is:

$g = \frac{\left(6.674\times 10^{-11}\,\frac{m^{3}}{kg\cdot s^{2}} \right)\cdot (5.972\times 10^{24}\,kg)}{(6.371\times 10^{6}\,m)^{2}}$

$g \approx 9.82\,\frac{m}{s^{2}}$

The magnitude of the gravitational field strength near Earth's surface is represented by approximately $9.82\,\frac{m}{s^{2}}$ .

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3 years ago

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Vilka [71]

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4 years ago

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