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Maru [420]
3 years ago
14

What are factors within a region that affect or limit the physical environment?

Physics
2 answers:
Bingel [31]3 years ago
8 0

\huge \tt \star \:  \red{Question}  \: \star

What are factors within a region that affect or limit the physical environment?

\huge \tt \star \: \red{Answer} \:  \star

Abiotic Factors. The most recognizable limitations to the geographic distribution of a species include insurmountable physical barriers, such as mountains, oceans, rivers, deserts, and, more recently, expansive human development.

NISA [10]3 years ago
6 0

Answer:Some examples of limiting factors are biotic, like food, mates, and competition with other organisms for resources. Others are abiotic, like space, temperature, altitude, and amount of sunlight available in an environment. Limiting factors are usually expressed as a lack of a particular resource.

Explanation:hope this helps you

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A magnetic field is decreasing in strength. According to Lenz's law, what prediction can be made about the magnetic field it ind
lesya692 [45]

Answer:

Did you ever get the answer?

Explanation:

8 0
3 years ago
A solid cylinder of mass 12.0 kgkg and radius 0.250 mm is free to rotate without friction around its central axis. If you do 75.
dybincka [34]

Answer:

The final angular velocity is 20rad/s

Explanation:

We are given;

mass, m = 12 kg

radius, r = 0.25 m

Work done;W = 75 J

Moment of inertia of cylinder, I = (1/2) mr²

Thus,

I = (1/2) x 12 x 0.25² = 0.375 kg.m²

Now, from work energy theorem,

Work done = Change in kinetic energy

So, W = KE_f - KE_i

Now, Initial Kinetic Energy (KE_i) = 0

Final Kinetic Energy; KE_f = (1/2)Iω²

So, KE_f = (1/2) x 0.375 x ω²

KE_f = 0.1875 ω²

Now, W = 75 J

Thus,

From, W = KE_f - KE_i, we have;

75 = 0.1875 ω² - 0

75 = 0.1875 ω²

ω² = 75/0.1875

ω² = 400

ω = √400

ω = 20 rad/s

5 0
3 years ago
2. Two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one o
rusak2 [61]

The rod is stretched due to the force of gravitational attraction.

The magnitude of the deformation force on the rod is  -GMm×((1/r² + 1/(L+r)²)

<h3>What is gravity?</h3>

The force of attraction felt by a person which is directed at the center of a planet or Earth is called as the gravity.

The force of attraction is directly proportional to the product of masses of the object and inversely proportional to the square of distance between them.

F = GMm/R²

Given are two small (green) objects, each of mass m, are separated by a solid, massless rod of length L. They are located so that one of the objects is located at a distance of r away from the center of a uniform spherical planet with mass M.  Assume that m is very small so that you can ignore the gravitational force between the two small (green) objects.

Let the mass closer to the planet is A and the other is B

FA = Force on planet A = -GMm/r²

FB = Force on planet B = -GMm/(L+r)²

Net Force on the rod is given by the addition of the individual forces.

Fnet= FA + FB = -GMm/r² -GMm/(L+r)²

Fnet = -GMm×((1/r² + 1/(L+r)²)

Thus,  the magnitude of the deformation force on the rod is derived above.

A experience more force than B, so A will stretch out from B. Hence the force is stretching the rod.

Learn more about gravity.

brainly.com/question/4014727

#SPJ1

8 0
2 years ago
Why does the desert sand, next to a lake, heat up quicker than the water in the lakes​
ICE Princess25 [194]

Water is a slow conductor of heat. Land absorbs heat quicker, so the sand next to the lake will heat up quicker than water.

4 0
4 years ago
If an element has 6 electrons, how many of them will be in the 2nd energy level?
Sergio039 [100]

1st \: answer \: is \:  \:  \:  \:  \:  \: 4
2nd \: answer \: is \:  \:  \:  \:  \: 109
3rd \: question \: is \: in complete
4th \: answer \: is \:  \:  \:  \: 87
5 0
3 years ago
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