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puteri [66]
4 years ago
13

What is the midpoint of the x-intercepts of f(x) = (x – 2)(x – 4)?

Mathematics
1 answer:
irakobra [83]4 years ago
6 0
2 and 4. (2,0) and (4,0)
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Yun is curious what proportion of users will click an advertisement that appears on his website. He takes a
My name is Ann [436]

Answer:

Step-by-step explanation:

4 0
3 years ago
First one right gets BRAINLIEST!!<br><br> If f(x)=x²+2x-3 and g(x)=x²-9, find (f/g) 4 and (f+g)(4)
Rasek [7]

Answer:

3 and 28

Step-by-step explanation:

note (\frac{f}{g} )(x ) = \frac{f(x)}{g(x)}

\frac{f(x)}{g(x)}

= \frac{x^2+2x-3}{x^2-9}  and

(\frac{f}{g} )(4) = \frac{4^2+2(4)-3}{4^2-9} = \frac{16+8-3}{16-9} = \frac{21}{7} = 3

-------------------------------------------------------

(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= x² + 2x - 3 + x² - 9 = 2x² + 2x - 12 and

(f + g)(4) = 2(4)² + 2(4) - 12 = 2(16) + 8 - 12 = 32 + 8 - 12 = 28

6 0
4 years ago
A hand held digital music player was marked down by 1/4 of the original price.
harina [27]

Answer:

160

Step-by-step explanation:


5 0
3 years ago
The beginning balance on a monthly bank statement for ignatius checking account was $124.82, and the ending balance was $659.27.
Brilliant_brown [7]

Answer:

He had 534.45 more in credits that debits

Step-by-step explanation:

Ignatius hd $534.45 more in credits than in debits. Since Ignatius had an initial balance of $124.82 at the beginning of the month and ended the month with $659.27 he was up money versus what he had in his account at the beginning of the month. During the month Ignatius made money that was credited to his account so that he ended it with a higher balance. 

8 0
4 years ago
Can someone help me find the fa tor of (128m^2n^5 - 200m^4n^3)? <br>​
Leona [35]

Answer:

8m^2n^3, 4n-5m, and 4n+5m

Step-by-step explanation:

128m^2n^5-200m^4n^3 <-- Given

m^2(128n^5-200m^2n^3) <-- Factor out m²

m^2n^3(128n^2-200m^2) <-- Factor out n³

8m^2n^3(16n^2-25m^2) <-- Factor out 8

8m^2n^3(4n-5m)(4n+5m) <-- Difference of Squares

Therefore, the factors are 8m^2n^3, 4n-5m, and 4n+5m

3 0
3 years ago
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