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iren [92.7K]
3 years ago
10

Solve the linear equation for x. –4.8(6.3x – 4.18) = –58.56

Mathematics
1 answer:
Mamont248 [21]3 years ago
4 0
X=2.6

step by step explanation:
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Write 1050.00 in words​
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Answer:

one thousand and fifty

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A typical roulette wheel used in a casino has 38 slots that are numbered 1, 2, 3, ... , 36, 0, 00, respectively The 0 and 00 slo
Tema [17]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

For point a:

Space for results All possible outcomes are:

\to O = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16,}

           17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, \\ 29, 30, 31, 32, 33, 34, 35, 36, 0, 00}

For point b:

\to P(A) = \frac{ \text{ \# of outcomes in A}}{ \text{ \# Total outcomes}} = \frac{2}{38} = 0.052

For point c:

\to P(B) = \frac{ \text{ \# of outcomes in B}}{\text{ \# Total outcomes}} = \frac{4}{38} = 0.105

For point d:

We consider that in D there are 18 elements (only Odd numbers in the range 1 to 36)

\to P(D) = \frac{ \text{\# of outcomes in D}}{\text{\# Total outcomes}} = \frac{18}{38} = 0.473

8 0
3 years ago
Find the solution set. |x|= 9<br> A. { }<br> B. {-3 , 3}<br> C. { -9, 9}<br> D. {-81, 81}
Ierofanga [76]

Answer:

C. { -9, 9}

Step-by-step explanation:

An absolute value equation has 2 solutions, a positive and a negative

|x|= 9

x= +9  and x = -9

4 0
3 years ago
Read 2 more answers
Customers arrive at a restaurant according to a Poisson distribution at a rate of 20 customers per hour. The restaurant opens fo
jenyasd209 [6]

Answer:

0.087

Step-by-step explanation:

Given that there were 17 customers at 11:07, probability of having 20 customers in the restaurant at 11:12 am could be computed as:

= Probability of having 3 customers in that 5 minute period. For every minute period, the number of customers coming can be modeled as:

X₅ ~ Poisson (20 (5/60))

X₅ ~ Poisson (1.6667)

Formula for computing probabilities for Poisson is as follows:

P (X=ₓ) = ((<em>e</em>^(-λ)) λˣ)/ₓ!

P(X₅= 3) = ((<em>e</em>^(-λ)) λˣ)/ₓ! =  (e^-1.6667)((1.6667²)/3!)

P(X₅= 3) = (2.718^(-1.6667))((2.78)/6)

P(X₅= 3) = (2.718^(-1.6667))0.46

P(X₅= 3) = 0.1889×0.46

P(X₅= 3) = 0.086894

P(X₅= 3) = 0.087

Therefore, the probability of having 20 customers in the restaurant at 11:12 am given that there were 17 customers at 11:07 am is 0.087.

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3 years ago
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Not more then a tenth of a nutshell

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