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borishaifa [10]
3 years ago
9

To complete a task in 15 days, a company has 4 people each working 8 hours a day. The company

Mathematics
1 answer:
Klio2033 [76]3 years ago
4 0

Answer:

Let's suppose that each person works at an hourly rate R.

Then if 4 people working 8 hours per day, a total of 15 days to complete the task, we can write this as:

4*R*(15*8 hours) = 1 task.

Whit this we can find the value of R.

R = 1 task/(4*15*8 h) = (1/480) task/hour.

a) Now suppose that we have 5 workers, and each one of them works 6 hours per day for a total of D days to complete the task, then we have the equation:

5*( (1/480) task/hour)*(D*6 hours) = 1 task.

We only need to isolate D, that is the number of days that will take the 5 workers to complete the task:

D = (1 task)/(5*6h*1/480 task/hour) = (1 task)/(30/480 taks) = 480/30 = 16

D = 16

Then the 5 workers working 6 hours per day, need 16 days to complete the job.

b) The assumption is that all workers work at the same rate R. If this was not the case (and each one worked at a different rate) we couldn't find the rate at which each worker completes the task (because we had not enough information), and then we would be incapable of completing the question.

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A $50 item was marked up 20%. What is the total increased cost of the item?​
GenaCL600 [577]

They increased it by $10.

It ended up costing $60.

Hope this helps.

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3 years ago
5TH GRADE LEVEL QUESTION. PLEASE LOOK AT PHOTO AND ANSWER AND PLEASE LIST STEP BY 1,2,3 GIVING BRAINLIEST.
Andrej [43]

Answer:

Step 1: 3*4=12

Step 2: 12+3=15

Step 3: 15-10=5

Step-by-step explanation:

8 0
3 years ago
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Please help me and If your answer is wrong or not appropreat I will report it
arsen [322]

Answer:

972 x^16 y^24

Step-by-step explanation:

Simplify the following:

(-2 x^3 y^7)^2 (3 x^2 y^2)^5

Multiply each exponent in -2 x^3 y^7 by 2:

(-2)^2 x^(2×3) y^(2×7) (3 x^2 y^2)^5

2×7 = 14:

(-2)^2 x^(2×3) y^14 (3 x^2 y^2)^5

2×3 = 6:

(-2)^2 x^6 y^14 (3 x^2 y^2)^5

(-2)^2 = 4:

4 x^6 y^14 (3 x^2 y^2)^5

Multiply each exponent in 3 x^2 y^2 by 5:

4 x^6 y^14×3^5 x^(5×2) y^(5×2)

5×2 = 10:

4×3^5 x^6 y^14 x^(5×2) y^10

5×2 = 10:

4×3^5 x^6 y^14 x^10 y^10

3^5 = 3×3^4 = 3 (3^2)^2:

4×3 (3^2)^2 x^6 y^14 x^10 y^10

3^2 = 9:

4×3×9^2 x^6 y^14 x^10 y^10

9^2 = 81:

4×3×81 x^6 y^14 x^10 y^10

3×81 = 243:

4×243 x^6 y^14 x^10 y^10

4 x^6 y^14×243 x^10 y^10 = 4 x^(6 + 10) y^(14 + 10)×243:

4×243 x^(6 + 10) y^(14 + 10)

14 + 10 = 24:

4×243 x^(6 + 10) y^24

6 + 10 = 16:

4×243 x^16 y^24

4×243 = 972:

Answer: 972 x^16 y^24

8 0
2 years ago
Read 2 more answers
What's the formula length and area with work plz!
dem82 [27]
You would have to put them into different shapes and the formula for the squares is sides^2 and the formula for the triangles is 1/2(b*h), eventually you will add the numbers together
5 0
3 years ago
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A triangle has a hypotenuse of 2.9ft and a leg of 2.6ft. Find the smallest angle.
OleMash [197]

Answer:

 Lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is   26.29°.

Explanation:

 A triangle has a hypotenuse of 2.9ft and a leg of 2.6ft

 We  have smallest angle = Angle C

 We have, Cos C = AC/BC

                            = 2.6/2.9

                           = 0.897

                      C = 26.29°

So lowest angle of the triangle with hypotenuse of 2.9ft and a leg of 2.6ft is   26.29°.

8 0
3 years ago
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