The rope is not long enough a meter is roughly 3 feet 3 inches totalling out to 98 feet and a few inches
Answer:
A. SAS
Step-by-step explanation:
If M is the midpoint of PQ, then PM and MQ are equal.
As PM and MQ are given , equal them to each other to solve for x.
7x+8=5x+20
Subtract 5x on both sides to get 2x+8=20
Subtract 8 on both sides to get 2x=12
divide by 2 on both sides to get x=6
Use the value of x=6 and plug it into the equations for PM and MQ to find their value.
PM=7x+8
=7(6) 8 =42 + 8 = 50
(you can already tell MQ is also 50 as PM and MQ are equal, but we still solve for MQ just for the fun of it)
MQ=5x + 20
=5(6) +20=30+20=50
PM=50
MQ=50
PQ= PM + MQ= 50 + 50 = 100
Have a great night.
Answer:
- a)
- b)
- c)
- d)
Step-by-step explanation:
We will use the product rule from combinatorics.
- a) There are 26 letters in the English alphabet, so there are 26 possible choices for the first character and 26 possible choices for the last one. Each one of the remaining eight characters of the string has 36 choices (letters or digits). By the product rule, there are
strings.
- b) We have 5 possible choices for the first character, it must be some vowel a,e,i,o,u. The second character can be chosen in 21 ways, selecting some consonant. There are 10 possibilities for the last character because only of the digits are allowed. The other seven characters have no restrictions, so each one can be chosen in 36 ways. By the product rule there are
strings.
- c) The third character has 5 possibilities. Repetition of vowels is allowed, so the sixth and eighth characters have each one 5 possible choices. There are seven characters left. None of them are a vowel, but they are allowed to take any other letter or digit, so each one of them can be chosen in 36-5=31 ways. Therefore there are strings.
- d) Remember that the binomial coefficient
is the number of ways of choosing k elements from a set of n elements. In this case, to count all the possible strings, we first need to count in how many ways we can select the four positions that will have the digits. This can be done in 
ways, since we are choosing four elements from the set of the ten positions of the string. Now, for the first position, we can choose any digit so it has 10 possibilities. The second position has 9 possibilities, because we can't repeat the digit used on the first position. Similarly, there are 8 choices for the third position and there are 7 choices for the fourth. Now, these are the only digits on the string, so the remaining 6 characters must be letters, then each one of them has 26 possibilities. By the product rule, there are strings.
Answer:
z = 5
x = 0
x = 1
Step-by-step explanation:
(z - 5)x^2 - (z - 5)x = 0 Take out z - 5 as a common factor
(z - 5)(x^2 - x) Take out x as a common factor
(z - 5)(x)(x - 1) Any one of these could equal 0. There are 3 solutons.
z - 5 = 0 Add 5 to both sides
z - 5 + 5 = 0 + 5
z = 5
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x = 0
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x - 1 = 0
x - 1 + 1 = 0 + 1
x = 1
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