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Olegator [25]
3 years ago
14

Rene has a coupon for $3.25 off a package of name brand cookies that normally costs $7.89. The store brand cookies coats $5.58.

How much will Rene save if she uses her coupon and buys the name brand cookies instead of the store brand cookies? HELP
Mathematics
1 answer:
allochka39001 [22]3 years ago
7 0
She would save 94 cents buying the name brand cookies
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2 years ago
A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting. It is
Volgvan

Answer:

Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

Step-by-step explanation:

We are given that a manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 430 gram setting.

It is believed that the machine is under filling the bags. A 21 bag sample had a mean of 429 grams with a variance of 289.

<u><em>Let </em></u>\mu<u><em> = mean weight bag filling capacity of machine.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 430 gram   {means that the machine is not under filling the bags}

Alternate Hypothesis, H_A : \mu < 430 gram   {means that the machine is under filling the bags}

The test statistics that will be used here is <u>One-sample t test statistics</u> as we don't know about the population standard deviation;

                        T.S.  = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean = 429 grams

             s = sample standard deviation = \sqrt{289} = 17 grams

             n = sample of bags = 21

So, <u><em>test statistics</em></u>  =  \frac{429-430}{\frac{17}{\sqrt{21} } }  ~ t_2_0   

                               =  -0.269

<em>Now at 0.01 significance level, the t table gives </em><u><em>critical value of -2.528 at 20 degree of freedom</em></u><em> for left-tailed test. Since our test statistics is higher than the critical value of t as -0.269 > -2.528, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which </em><u><em>we fail to reject our null hypothesis</em></u><em>.</em>

Therefore, we conclude that the machine is not under filling the bags.

3 0
3 years ago
Solve this systems of equation word problem. please
agasfer [191]
2b+h = 4.82
b+2h = 3.70
multiply the second equation by 2:
2b + 4h = 7.40
subtract the first equation from it:
3h = 2.58
h = 0.86
5 0
3 years ago
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