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pantera1 [17]
3 years ago
14

If winds blow against a mountain from the south then in which slope would you expect to find the least precipitation

Chemistry
2 answers:
N76 [4]3 years ago
7 0
The opposite side of that mountain
Nikitich [7]3 years ago
6 0

The north side! :D

Hope this wasnt too late and helps out!

:3

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What is the subscript present in NaCl?
jonny [76]

Answer:

NaCl or sodium chloride, is commonly known as table salt. ... Subscripts show the ratio of atoms of different elements in the compound. Since there are four hydrogen atoms in the molecule, the subscript 4 follows the symbol for hydrogen.

Explanation:

3 0
4 years ago
Read 2 more answers
El superóxido de potasio, KO2, se emplea en máscaras de respiración para generar
Orlov [11]

Answer:

Reactivo límite: Superóxido de potasio.

Moles de oxígeno producidas: n_{O_2}=0.11molO_2

Explanation:

Hola,

En este caso, considerando la reacción química llevada a cabo:

4KO_2(s) + 2H_2O(l) \rightarrow 4KOH(s) + 3O_2(g)

Es posible identificar el reactivo límite calculando las moles de superóxido de potasio que serían consumidas por 0.10 mol de agua por medio de la relación molar 4 a 2 que hay entre ellos:

n_{KO_2}^{consumido\ por\ agua}=0.10molH_2O*\frac{4molKO_2}{2molH_2O} =0.2molKO_2

Así, dado que solo hay 0.15 mol the superóxido de potasio, podemos decir que este es el reactivo límite. Luego, calculamos las moles de oxígeno producidas, considerando la relación molar 4 a 3 que hay entre el superóxido y el oxígeno:

n_{O_2}=0.15molKO_2*\frac{3molO_2}{4molKO_2} \\\\n_{O_2}=0.11molO_2

Best regards.

4 0
3 years ago
each body cell of a goldfish contains 94 chromosomes.how many chromosomes are contained in a goldfish sex cell?
Shalnov [3]
47 I believe not 100% sure
8 0
3 years ago
How many moles do 9.2 g of Al(NO3)3 represent?
photoshop1234 [79]
Answer:

0.04319325114089596
6 0
3 years ago
Complete combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO2 and 12.2 g of H2O. What is the empirical formula for the h
amid [387]

The empirical formula of the hydrocarbon is C_2H_3 if combustion of 8.60 g of a hydrocarbon produced 26.5 g of CO_2 and 12.2 g of H_2O.

<h3>What is an empirical formula?</h3>

A chemical formula showing the simplest ratio of elements in a compound rather than the total number of atoms in the molecule CH_2O is the empirical formula for glucose.

1 mole of carbon dioxide contains a mass of 44 g, out of which 12 g are carbon.

Hence, in this case the mass of carbon in 8.46 g of CO_2:

(\frac{12}{44}) × 8.46 = 2.3073 g

1 mole of water contains 18 g, out of which 2 g is hydrogen;

Therefore, 2.6 g of water contains;

(\frac{2}{18} × 2.6 = 0.2889 g of hydrogen.

Therefore, with the amount of carbon and hydrogen from the hydrocarbon, we can calculate the empirical formula.

We first calculate the number of moles of each,

Carbon = \frac{2.3073}{12}  = 0.1923 moles

Hydrogen = \frac{0.2889}{1}= 0.2889 moles

Then, we calculate the ratio of Carbon to hydrogen by dividing by the smallest number value;

            Carbon : Hydrogen

               \frac{0.1923}{0.1923} : \frac{0.2889}{0.1923}

                      1 :  1.5

                     (1 : 1.5) 2

                    = 2 : 3

Hence, the empirical formula of the hydrocarbon is C_2H_3.

Learn  more about the empirical formula here:

brainly.com/question/14044066

#SPJ1

8 0
2 years ago
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