Answer:
131.2 mL would be the total volume in the graduated cylinder.
Explanation:
Let's work with the density of metal to find out its volume
Metal density = Metal mass / metal volume
4.46 g/mL = 22.25 g / metal volume
Metal volume = 22.25 g / 4.46 g/mL = 4.98 mL
If we suppose aditive volume, total volume in the graduated cylinder will be:
126.3mL + 4.9mL = 131.2 mL
In the given <span>phase diagram, the line segment that describes the interface between solid and vapor is A-B. The rest of the choices do not answer teh question above</span>
Answer:
They are able to perform all necessary functions within one cell.
Explanation:
Answer:
I am almost done
Explanation:
21.0 L
↓
2H₂(g) + O₂(g) → 2H₂O(l)
↑
4.67 × 10²⁴ moles
[This is done so the equation is balanced and the reaction can occur]
[subscripts are the number of atoms, and the coefficients are the number of molecules]
______________
Since there are about 6.02 × 10²³ moles in one mol of a substance.
4.67 × 10²⁴ / 6.02 × 10²³ =
7.7547174437 mol.
Next, we must determine the grams per mole of each substance, this can be done with the periodic table.
Since hydrogen, and oxygen gas are diatomic, they will consist of two atoms each. So the atomic mass will be multiplied by 2 to get the molecular mass. Therefore H₂ will have a molecular mass of 1.00794 × 2 = 2.01588 g/mol.
