A) 2 is the correct answer
I don’t have a picture but I can describe it to you.
The hydrogen that is attached at the tertiary position on the heptatriene (at the 7-methyl) would be very acidic, as removal would leave a positive charge that could be moved throughout the ring through resonance. This would mean that the three double bonds would be participating in resonance, and the deprotonated structure would be aromatic, thus making this favorable.
The hydrogen that is attached at the tertiary position on the pentadiene (5-methyl) would NOT be acidic, as removal would cause an antiaromatic structure.
Any other hydrogens would NOT be acidic. Those vinylic to their respective double bonds would seriously destabilize the double bond if removed, and hydrogens attached to the methyl group jutting off the ring have no incentive to leave the carbon.
Hope this helps!
I would say it is B because when u pull ur leg up the space in your muscles are smaller when you spread your leg out they relax because they are not pulling anything.<span />
Answer:As you have asked, I will not do your homework for you but will outline the reasoning…
Find out the atomic weight of all the species involved in the problem. Three decimals is more than sufficient.
Look at the periodic table of the elements and other resources (notes!) as necessary to determine the expected valence of the species
Once you know how many of these go with those, you are cruising…
You already know that 4Al+3O2→2Al2O3
So, you are in a great position to determine the number of moles of O2 , as you know you have 14.8 mol of Al and the ratio of combination is always 4 molecules.
Explanation:
Explanation:
<h2>A. Calculating the molar mass of the ending compound.</h2>
