Question

If n ^-2 = 1/16, then n could be which of the following?

Answer 1

$n^{-2} =\frac{1}{n^2}\\\\\frac{1}{n^2}=\frac{1}{16} \\\\n^2 =16\\\\n =\pm 4\\\\\boxed{\bf{n=4}}\\\\\boxed{\bf{n=-4}}\\\\\\\\\boxed{\bf{4^{-2} =\frac{1}{16}}}\\\\\boxed{\bf{(-4)^{-2} =\frac{1}{16}}}$