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4 years ago

Can you do 8 9for me

Mathematics

2 answers:

vitfil [10]4 years ago

6 0

Answer:

The answer to 9 is 358

Step-by-step explanation:

inna [77]4 years ago

4 0

The answer to #9 is -> 358

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The two-way table shows the distribution of gender to favorite film genre for the senior class at Mt. Rose High School.

Studentka2010 [4]

Answer:

The second statement is correct

Step-by-step explanation:

Hello!

The table shows the information of the favorite film genre of the students of the class regarding their gender.

You have to prove which statement is correct:

1)The probability of randomly selecting a student who has a favorite genre of drama and is also female is about 17 percent.

If you chose a student at random, you need to calculate the probability of its favorite genre being "Drama" (D) and the student being female (F), symbolically: P(D∩F)

To do so you have to divide the number of observed students that are female and like drama by the total number of students:

P(D∩F)= $\frac{24}{240}= \frac{1}{10} =0.10$

This means that the probability of choosing a student at random and it being a female that likes drama is 10%.

This statement is incorrect.

2) Event F for female and event D for drama are independent events.

Two events are independent when the occurrence of one of them doesn't affect the probability of occurrence of the other one.

So if F and D are independent then:

P(F)= P(F|D)

-or-

P(D)=P(D|F)

The probability of the event "Female" is equal to $P(F)= \frac{Total females in the class}{n} = \frac{144}{240} = \frac{3}{5}= 0.6$

The probability of the event "Drama" is:

$P(D)= \frac{Total students that like "Drama"}{n}= \frac{40}{240}= \frac{1}{6}= 0.166$

$P(F|D)= \frac{P(FnD)}{P(D)}= \frac{\frac{1}{10} }{\frac{1}{6} }= \frac{3}{5} = 0.6$

As you can see P(F)= 0.6 and P(F|D)= 0.6 so both events are independent.

This statement is correct.

3) The probability of randomly selecting a male student, given that his favorite genre is horror, is 16/40

This is a conditional probability, you already know that the student likes horror movies (H), and out of that group you want to know the probability of the student being male (M):

$P(M|H)= \frac{number of male students that like horror movies}{total students that like horror movies}= \frac{16}{38}= \frac{8}{19} = 0.42$

This statement is incorrect.

4) Event M for male and event A for action are independent events.

Same as the second statement, if the events "Male" and "Action" are independent then:

P(M)= P(M|A)

-or-

P(A)= P(A|M)

$P(M)= \frac{96}{240}= \frac{2}{5}= 0.4$

$P(A)= \frac{72}{240} =\frac{3}{10}= 0.3$

$P(AnM)= \frac{28}{240}= \frac{7}{60}= 0.11666$

$P(M|A)= \frac{P(MnA)}{P(A)}= \frac{\frac{7}{60} }{\frac{3}{10} } = \frac{7}{18}= 0.3888$

$P(M)= \frac{2}{5}$ and $P(M|A)= \frac{7}{18}$

P(M)≠ P(M|A) the events are not independent.

This statement is incorrect.

I hope this helps!

6 0

3 years ago

Stacy is selling tickets to the school play. The tickets are $7 for adults and $4 for children she sells twice as many adult tic

ElenaW [278]

Stacy sold 15 children tickets and 30 adult tickets.

The tickets are $7 for adults and $4 for children.

She sells twice as many adult tickets as children tickets and bring in a total of $270.

Therefore,

let

number of children ticket sold = x

number of adult ticket sold = 2x

7(2x) + 4(x) = 270

14x + 4x = 270

18x = 270

x = 270 / 18

x = 15

The number of children ticket sold = 15

The number of adult ticket sold = 15 × 2 = 30

learn more about algebra here: brainly.com/question/14569336?referrer=searchResults

5 0

2 years ago

Three microcontrollers are needed to operate a specific type of robot. Such a robot stops working whenever one or more microcont

Xelga [282]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

The robot will work only if all the micro controller works on the competition day.

The probability of the micro controller's failing is $\frac{1}{2}$ .

The probability of the micro controller's success is $\frac{1}{2}$ .

Hence, the required probability is $\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} = \frac{1}{8}$ .

(b)

From the three micro controller, one can be chosen in $^3C_1 = 3$ ways.

The probability here is $\frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}\times3 = \frac{3}{8}$ .

(c)

If from the four micro controllers, one fails, then also they can manage to make the robot work.

From the 4, 1 can be chosen in 4 ways.

This one can either work properly or not.

If it works properly, then the probability of other 3 will work properly is $(\frac{1}{2} )^4 = \frac{1}{16}$ .

If the chosen one does not work properly, then the probability of other 3 will work properly is $(\frac{1}{2} )^4 = \frac{1}{16}$ .

The required probability is $3(\frac{1}{16} + \frac{1}{16} ) = \frac{3}{8}$ .

(d)

In this case there are total 6 micro controllers.

From these 6 controllers, 3 can be chosen as $^6C_3 = \frac{6!}{3!\times3!} = 20$ ways.

The probability that the team is able to reshuffle the micro controllers to make one robot work is $20\times(\frac{1}{2} )^6 = \frac{5}{16}$ .

3 0

4 years ago

How you would find the exterior angle if you know the two remote interior angles? open add class comment…?

andreyandreev [35.5K]

The measure of the exterior angle is the sum of the two remote interior angles. So add ur 2 remote interior angles, and that will be the measure of the exterior angle

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3 years ago

Which two numbers add up to23 and multiply to 180

iris [78.8K]

They add up two:

11 and 1 half

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3 years ago