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IgorLugansk [536]

4 years ago

13

Can you do 8 9for me

2 answers:

vitfil [10]4 years ago

6 0

Answer:

The answer to 9 is 358

Step-by-step explanation:

inna [77]4 years ago

4 0

The answer to #9 is -> 358

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Find the length of an arc of 40° in a circle with an 8 inch radius.

lora16 [44]

The length of an arc is the fraction of its circumference based on the given intercepted angle. This is given by the equation,
L (arc) = (Angle / 360) x 2πr
Substituting the known values,
L (arc) = (40 / 360) x 2π(8 inch) = 16π/9 inch
Thus, the length of the arc is approximately equal to 5.585 inches.

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4 years ago

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According to your graphing calculator, what is the approximate solution to the trigonometric inequality cot(x)> -7/8 over the

marta [7]

Answer:

Option C

Step-by-step explanation:

See attached the graphical solution

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3 years ago

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Why is the answer to this integral's denominator have 1+pi^2

ss7ja [257]

It comes from integrating by parts twice. Let

$I = \displaystyle \int e^n \sin(\pi n) \, dn$

Recall the IBP formula,

$\displaystyle \int u \, dv = uv - \int v \, du$

Let

$u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Then

$\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn$

Apply IBP once more, with

$u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn$

$dv = e^n \, dn \implies v = e^n$

Notice that the ∫ v du term contains the original integral, so that

$\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)$

$\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I$

$\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n$

$\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C$

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2 years ago

What the value of x 4(2x-5)=5x+4

mrs_skeptik [129]

x=8

hope this helps you

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3 years ago

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Need some help just can’t understand

allochka39001 [22]

Answer:

Positive I think

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3 years ago

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