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3 years ago

5

what is 17 approxipated to the nerest tenth plz answer right will give brainlist show work if possibale thanks

1 answer:

Katen [24]3 years ago

3 0

Hey !!

Check the attachment.
Hope it helps you :)

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How would you prove these two triangles conrguent?

Crank

Answer:

SSS

Step-by-step explanation:

4 0

3 years ago

If x-y = 40 and x+y = 70, then what is the value of x squared -y squared ?

OlgaM077 [116]

Let's see what to do buddy...

____________________________

Reminder:

$(a + b)(a - b) = {a}^{2} - {b}^{2}$

So we need to just Multiply above equations like this :

$x + y = 70$

$x - y = 40$

$(x + y)(x - y) = 70 \times 40$

${x}^{2} - {y}^{2} = 2800$

____________________________

And we're done.

Thanks for watching buddy good luck.

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7 0

3 years ago

Hypothesis Test by Hand

inna [77]

Answer:

ummm i think it is b or c no its b becuse nah i not gone tell u

Step-by-step explanation:

6 0

3 years ago

1. Express <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bx%282x%2B3%29%20%7D" id="TexFormula1" title="\frac{1}{x(2x+3) }" a

katovenus [111]

1. Let a and b be coefficients such that

$\dfrac1{x(2x+3)} = \dfrac ax + \dfrac b{2x+3}$

Combining the fractions on the right gives

$\dfrac1{x(2x+3)} = \dfrac{a(2x+3) + bx}{x(2x+3)}$

$\implies 1 = (2a+b)x + 3a$

$\implies \begin{cases}3a=1 \\ 2a+b=0\end{cases} \implies a=\dfrac13, b = -\dfrac23$

so that

$\dfrac1{x(2x+3)} = \boxed{\dfrac13 \left(\dfrac1x - \dfrac2{2x+3}\right)}$

2. a. The given ODE is separable as

$x(2x+3) \dfrac{dy}dx} = y \implies \dfrac{dy}y = \dfrac{dx}{x(2x+3)}$

Using the result of part (1), integrating both sides gives

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + C$

Given that y = 1 when x = 1, we find

$\ln|1| = \dfrac13 \left(\ln|1| - \ln|5|\right) + C \implies C = \dfrac13\ln(5)$

so the particular solution to the ODE is

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3|\right) + \dfrac13\ln(5)$

We can solve this explicitly for y :

$\ln|y| = \dfrac13 \left(\ln|x| - \ln|2x+3| + \ln(5)\right)$

$\ln|y| = \dfrac13 \ln\left|\dfrac{5x}{2x+3}\right|$

$\ln|y| = \ln\left|\sqrt[3]{\dfrac{5x}{2x+3}}\right|$

$\boxed{y = \sqrt[3]{\dfrac{5x}{2x+3}}}$

2. b. When x = 9, we get

$y = \sqrt[3]{\dfrac{45}{21}} = \sqrt[3]{\dfrac{15}7} \approx \boxed{1.29}$

8 0

2 years ago

What is the value of the x variable in the solution to the following system of equations? 2x - 3y = 3

scZoUnD [109]

Answer:

(0,-1)

value x is 0

value y is -1

8 0

2 years ago