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vladimir1956 [14]
3 years ago
9

Find the equation of the parable in general form by completing the square. Then, state its vertex

Mathematics
1 answer:
lora16 [44]3 years ago
6 0
The parabola will show the vertex in the format: y-k = (x-h)^2, where the vertex point
lies at (h, k).
so \: for \:  {x}^{2}  + 2x - y + 3 = 0
let's first put it in "y =" standard format:
y =  {x}^{2}  + 2x + 3
Since we cannot get a perfect square out of this, we complete the square: a=1, b=2, c=3
(b/2)^2 = (2/2)^2 = 1, so
y =  {(x +1)}^{2} ...\: is \: y =  {x}^{2}  + 2x + 1
So there's +2 leftover, since 3-1=2; so:
y =  {(x + 1)}^{2}  + 2
Now we'll subtract the 2 from both sides to show our vertex:
y - 2 =  {(x + 1)}^{2}
where our vertex (h, k) is at (-1, 2)
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Same the same rule applies to the second option as well as the last.

Your answer is C. or the third option
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Hope this Helps
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The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi
Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872

From central limit theorem, we have:

z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}

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Here, n = 1 minute = 60 seconds

P(x > 950)

P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)

= 1 - P(z \leq 1.667)

Calculation the value from standard normal z table, we have,  

P(x > 950) = 1 - 0.952 = 0.048

0.048 is the probability that more than 950 message arrive in one minute.

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3 years ago
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Answer:

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Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

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