Answer:
y=-37
Step-by-step explanation:
0+6y=7(y+6)-5
0+6y=7y+42-5
6y=7y+37
-1y=37
y=-37
First, you need to move 2 to the other side. You accomplish this by adding 2 to 1. You have y>3. Since your variable is smaller than 3, draw an open circle on the 3 mark and a squiggly line left of 3.
<em>x = -4 is a vertical asymptote for the function.</em>
<h2>
Explanation:</h2>
The graph of
is a vertical has an asymptote at
if at least one of the following statements is true:

The function is:

First of all, let't factor out:

From here:


Accordingly:

<h2>Learn more:</h2>
Vertical and horizontal asymptotes: brainly.com/question/10254973
#LearnWithBrainly
To find the mean add up all the numbers and divide. The mean absolute deviation is the difference.
181818/1000000. let me know if im wrong! <3