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3 years ago

In a permanent magnet,

Physics

1 answer:

VARVARA [1.3K]3 years ago

7 0

A is the best answer. This is what makes the magnetic field of the magnet.

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A box with a mass of 12.5 kg sits on the floor. how high would you need to lift it for it to have a gpe of 355 j

grandymaker [24]

Gpe=mgh

355=12.5×10×h
h=355/125= 2.84m

3 0

4 years ago

Serving at a speed of 164 km/h, a tennis player hits the ball at a height of 2.23 m and an angle θ below the horizontal. The ser

sweet-ann [11.9K]

Answer:

The angle θ is 6.1° below the horizontal.

Explanation:

Please, see the figure for a description of the situation.

The vector "r" gives the position of the ball and can be expressed as the sum of the vectors rx + ry (see figure).

We know the magnitude of these vectors:

magnitude rx = 11.6 m

magnitude ry = 2.23 m - 0.99 m = 1.24 m

Then:

rx = (11. 6 m, 0)

ry = (0, -1.24 m)

r = (11.6 m + 0 m, 0 m - 1.24 m) = (11.6 m, -1.24 m)

Using trigonometry of right triangles:

magnitude rx = r * cos θ = 11. 6 m

magnitude ry = r * sin θ = 2.23 m - 0.99 = 1.24 m

where r is the magnitude of the vector r

magnitude of vector r:

$r = \sqrt{(11.6m)^{2} + (1.24m)^{2}} = 11.667m$

Then:

cos θ = 11.6 m / 11.667 m

θ = 6.1°

Using ry, we should obtain the same value of θ:

sin θ = 1.24 m/ 11.667 m

θ = 6.1°

( the exact value is obtained if we do not round the module of r)

7 0

3 years ago

When birds remain airborne and moving without flapping their wings, on what are they gliding?

bogdanovich [222]

They're riding on thermals, these are rising columns of air caused by the uneven heating of Earth's surface from solar radiation.

Hope this helped!

8 0

3 years ago

Read 2 more answers

A jet plane comes in for a downward dive as shown in the figure below.

xxTIMURxx [149]

The solution would be like this for this specific problem:

5.5 g = g + v^2/r 
4.5 g = v^2/r 
v^2 = 4.5 g * r 
v = sqrt ( 4.5 *9.81m/s^2 * 350 m) 
v = 124 m/s

So the pilot will black out for this dive at 124 m/s. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

8 0

3 years ago

Read 2 more answers

Suppose that the speed of yellow visible light in a certain transparent medium is 2.01* 105 km/s. What, approximately, is the in

True [87]

Answer:

$1.50$

Explanation:

Index of refraction:

$n=\frac{c}{v}$ where $n$ is the refractive index, $c$ is the speed of light in vacuum and $v$ is the speed of light in medium.

The speed of light in vacuum is $3.00 \times 10^5 \text{km/s}$

Speed of light in medium is $2.01 \times 10^5 \text{km/s}$

Thus,

$n=\frac{3.00\times 10^5}{2.01\times 10^5}$

$n=1.50$

Index of refraction of this substance through yellow light is $1.50$

4 0

3 years ago